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c = ek1(dk2(ek3(p)) dk1(c)= dk2(ek3(p)) If you decrypt c with a random key and store in a table of size n Try k2 and k3 and see if the result is in the table. If the result is in the table you are done. 64 bit text resulting in a 64 bit cipher The probability of it being in the table is n/264 The number of trials is 264/n Larger storage n => Less trials n = 232 => 232 trials

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Raj Jain Washington University in St. Louis 6-34

Posted By Qasim Siddique Department of Computer Science FUIEMS

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