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How does the period revolution relate to semimajor axis?
The period revolution of an orbiting body is directly related to its semimajor axis through Kepler's Third Law of Planetary Motion. This law states that the square of the orbital period (T) of a planet is directly proportional to the cube of the semimajor axis (a) of its orbit, expressed mathematically as T² ∝ a³. This means that as the semimajor axis increases, the orbital period increases as well, indicating that objects further from a central body take longer to complete an orbit.
If a semimajor axis is 2.77au what is period of Ceres years?
Using Kepler's third law, the period (P) of an object in orbit can be calculated using the formula P^2 = a^3, where a is the semimajor axis in astronomical units (au). For Ceres with a semimajor axis of 2.77 au, the period of its orbit around the Sun is approximately 4.61 years.
What does the semimajor axis of a planet with a period of 12 earth years measure?
That can be calculated from Kepler's 3rd law which says if the period is T years the semimajor axis must be T2/3 astronomical units. So for a period of 12 years the s/m axis is 5.421 AU or 784 million km.
What is the eccentricity of an ellipse in which the distance between the foci is 2 centimeters and the length of the major axis is 5 centimeters?
The eccentricity of that ellipse is 0.4 .
Suppose astronomers discover a new planet orbiting your sunthe orbit has a semimajor axis of 2.52 AU what is the planets period of revolution?
The period of revolution can be calculated using Kepler's Third Law: P^2 = a^3, where P is the period in years and a is the semimajor axis in astronomical units (AU). In this case, the period of revolution of the planet would be approximately 4.00 years.
How do Keplers 3 laws of motion combined with the parts of an ellipse explain the amount of time it takes for a planet to orbit the sun based on its length?
One of the parts of an ellipse is the length of its major axis. Half that is called the semimajor axis. Kepler's 3rd law says that the time to do one orbit is proportional to the 3/2 power of the semimajor axis. IF the semimajor axis is one astronomical unit the period is one year (the Earth). For a planet with a semimajor axis of 4 AUs the period would have to be 8 years, by Kepler-3.
How do Kepler's 3 laws of motion combined with the parts of an ellipse explain the amount of time it takes for a planet to orbit the sun based on its length?
One of the parts of an ellipse is the length of its major axis. Half that is called the semimajor axis. Kepler's 3rd law says that the time to do one orbit is proportional to the 3/2 power of the semimajor axis. IF the semimajor axis is one astronomical unit the period is one year (the Earth). For a planet with a semimajor axis of 4 AUs the period would have to be 8 years, by Kepler-3.
What is also known as the semimajor axis?
The major axis of an ellipse is its longest diameter, a line that runs through the center and both foci, its ends being at the widest points of the shape.The semi-major axis is one half of the major axis, and thus runs from the centre, through a focus, and to the edge of the ellipse. It represents a "long radius" of the ellipse, and is the "average" distance of an orbiting planet or moon from its parent body.
What is the semimajor axis of Mercury's orbit around the Sun?
Oh, an interesting question! Mercury's semimajor axis - which is the distance from the center of the Sun to the farthest point of Mercury's orbit - is about 0.39 astronomical units, or around 57.9 million kilometers. That's a nice and cozy space for our little Mercury to dance gracefully around the warm Sun. Nature has a way of creating beauty in all the details like this, doesn't it?
What is the semimajor axis of a circle of diameter 24 cm?
The major and minor axes of a circle are the same - either is any diameter. So a semimajor axis is half the diameter which is 12 cm.
What is the value of moment of inertia of ellipse about x-Axis?
Moment of inertia about x-axis for an ellipse is = pi*b^3*a /4. Where b is the distance from the center of the ellipse to the outside tip of the minor axis. a is the distance from the ceneter of the ellipse to the outside tip of the major axis. Moment of inertia about x-axis for an ellipse is = pi*b^3*a /4. Where b is the distance from the center of the ellipse to the outside tip of the minor axis. a is the distance from the ceneter of the ellipse to the outside tip of the major axis.
What is equal to the length of the major axis of an ellipse?
The length of the major axis of an ellipse is equal to twice the length of the semi-major axis. If the semi-major axis is denoted as "a," then the major axis length is 2a. This axis is the longest diameter of the ellipse, stretching from one end of the ellipse to the other through the center.
The period of revolution is related to?
the period of revolution is related to the semimajor axis.... :)
How does the period revolution relate to semimajor axis?
The period revolution of an orbiting body is directly related to its semimajor axis through Kepler's Third Law of Planetary Motion. This law states that the square of the orbital period (T) of a planet is directly proportional to the cube of the semimajor axis (a) of its orbit, expressed mathematically as T² ∝ a³. This means that as the semimajor axis increases, the orbital period increases as well, indicating that objects further from a central body take longer to complete an orbit.
If a semimajor axis is 2.77au what is period of Ceres years?
Using Kepler's third law, the period (P) of an object in orbit can be calculated using the formula P^2 = a^3, where a is the semimajor axis in astronomical units (au). For Ceres with a semimajor axis of 2.77 au, the period of its orbit around the Sun is approximately 4.61 years.
Does the foci of an ellipse lie on the major axis of the ellipse?
yes
What is the significance of the semimajor axis of planets in understanding their orbits and distances from the sun?
The semimajor axis of a planet's orbit is important because it determines the size and shape of the orbit, as well as the distance of the planet from the sun. It helps us understand the planet's position in relation to the sun and other planets, and provides valuable information about the planet's orbital characteristics.
