The amperage limit for a circuit is determined by the wire size and the rating of the circuit breaker. It is important to use the correct wire size and breaker to prevent overheating and potential fire hazards. It is recommended to consult a professional electrician to ensure safety and compliance with electrical codes.
The amperage limit of a number 2 gauge wire can vary depending on the insulation type and the application. In general, number 2 gauge wire can typically handle around 95-115 amps for power transmission. However, it is important to consult the specific wire manufacturer's specifications and applicable electrical codes to determine the exact amperage limit for your particular application.
Each appliance has its own amperage. This can be shown by looking at the label of each appliance. A circuit is protected by a breaker which has a trip limit. By continually adding more amperage from different appliances, the circuit becomes overloaded. When the circuits limit is reached because of the additive effect of more appliances to the circuit the breaker will trip. This disconnects the appliance loads from the distribution panel supply and prevents over loading of the conductors of that circuit. Without removing some of the load amperage, the breaker will keep tripping when reset.
To calculate the amperage, you need to know the resistance in the circuit. Amperage is calculated using Ohm's Law: Amperage (A) = Voltage (V) / Resistance (R). Without knowing the resistance, we cannot determine the amperage.
To calculate the amperage, you can use the formula: Amperage = Watts / Volts. Thus, for 10,000 watts at 240 volts, the amperage would be 41.67 Amps.
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
20 Amp
Typically 30 amps.
The amperage limit of a number 2 gauge wire can vary depending on the insulation type and the application. In general, number 2 gauge wire can typically handle around 95-115 amps for power transmission. However, it is important to consult the specific wire manufacturer's specifications and applicable electrical codes to determine the exact amperage limit for your particular application.
Amperage is electric current of flow.
Circuits are limited for a few reasons firstly because certain size wiring can only handle so much voltage and amperage before it could fail secondly wiring heats up when more amperage is drawn through it which can create fires or burning out of the circuit most appliances draw set amount of current and amperage if you have a low amperage appliance Eg pool pump drawing 4 amps and the windings start to fail the motor can start drawing excessive amperage creating a hazard, if you had a large circuit it may never trip the breaker indicating a fault with the appliance which can cause catastrophic failure.
It is ok to use a fuse with a higher amperage rating and not ok to use a fuse with a smaller amperage rating why?
Each appliance has its own amperage. This can be shown by looking at the label of each appliance. A circuit is protected by a breaker which has a trip limit. By continually adding more amperage from different appliances, the circuit becomes overloaded. When the circuits limit is reached because of the additive effect of more appliances to the circuit the breaker will trip. This disconnects the appliance loads from the distribution panel supply and prevents over loading of the conductors of that circuit. Without removing some of the load amperage, the breaker will keep tripping when reset.
This doesn't make sense, "current" is "amperage" so the higher the voltage the lower the amperage, and the lower the voltage the higher the amperage.
There is no proper amperage...no such thing as amperage, its called current... measured in amps...
Wire size is based on the amperage drawn. To find the amperage, the voltage must be stated. Use this formula to find the amperage. I = W/E. Amps = Watts/ Volts. Once you have the amperage, restate your question using the new found amperage or state the voltage that supplies the lights.
An amperage is the electric current's strength carried by a conductor or machine generated as measured in amperes.
a ten-wrap amperage multiplier is used with a (n)