BOTH Li and Na have ns1 in common which comes at last of their electronic configuration as they belong to IA subgroup.
the electron dot structure for lithium is Li ' (the element symbol with one dot on the upper right side)
Sodium is atomic number 11 so it has 11 electrons. The electronic configuration would be 1s2 2s2 2p6 3s1.
Argon has the same electron configuration as a sodium ion. Sodium ion has lost 1 electron from its outer shell, making its electronic configuration 2, 8. Argon's electronic configuration is also 2, 8 in its outer shell.
The alkali metal cations are lithium (Li+), sodium (Na+), potassium (K+), rubidium (Rb+), cesium (Cs+), and francium (Fr+). These cations are formed when alkali metals lose their outermost electron to achieve a stable electron configuration.
Electron arrangementsLi 2.1Na 2.8.1K 2.8.8.1Rb 2.8.8.18.1Cs 2.8.8.18.18.1
2,8,1
na + cl- na - electronic configuration 2,8,1 cl - electronic configuration 2,8,7 na -e --> na + cl +e -->cl - so they formed a ironic bond between them
+!. The lakali metals are Li, Na K etc in group 1 with an electronic configuration with just ns1 as the outer shell.
the electron dot structure for lithium is Li ' (the element symbol with one dot on the upper right side)
The ion formed when sodium achieves a noble-gas electronic configuration is Na+. This means that sodium has lost one electron to achieve the same electron configuration as neon, a noble gas, which has a stable electron configuration.
Sodium is atomic number 11 so it has 11 electrons. The electronic configuration would be 1s2 2s2 2p6 3s1.
Argon has the same electron configuration as a sodium ion. Sodium ion has lost 1 electron from its outer shell, making its electronic configuration 2, 8. Argon's electronic configuration is also 2, 8 in its outer shell.
No, sodium (Na) is more chemically reactive than lithium (Li) because sodium has an outer electron configuration that makes it more likely to lose an electron and form compounds.
Not at all! It is mostly used when someone compliments you. The modest reply would be "na li, na li!" (那里)
The electronic configuration for the sodium ion, Na+ is 1s2 2s2 2p6 or [Ne]
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
If it has 11 electrons it must have 11 protons to balance the charge. So the element is Na. But you know it's going to be an isotope of Na since the number of protons and number of neutrons are different. To find out which isotope you have, you must get the mass number which is just the number of protons plus the number of neutrons (remember, they are the only ones that have mass) 11+12= 23 So you have Na-23