Yes, but you also have to pay attention to how many molecules of each element are in the compound.
For instance: H2O (water)
The weight of H is roughly 1 and the weight of O is roughly 16, but formula weight of water is NOT equivalent to just 1 + 16 = 17
You have to be sure that you account for the total amount of molecules so since there are 2 H present you have to multiply the weight of H by 2; 1 x 2 = 2
Now you have the weight of all the H present and just add that to the weight of the single O molecule
2 + 16 = 18; thus the formula weight of water is 18.
It is an empirical formula.
A formula unit is an empirical formula.
An empirical formula has no data about the structure of a compound.
It has a molecular formula of C10H8 so that would make an empirical formula of C5H4.
The empirical formula for estriol is C18H24O3.
HgF
C10H22 is the empirical formula of decane.
The empirical formula of N3P3Cl6 is NPCl2. This is determined by dividing all the subscripts in the formula by the greatest common factor, which is 3 in this case.
The empirical formula of glucose is the formula which has the lowest ratio. You can divide all three elements by 6 to give: CH2O.
The empirical formula for x39y13 is x3y. This is determined by finding the simplest whole number ratio of the subscripts x and y in the compound.
Not completely. The empirical formula of a substance can be determined from its percent composition, but a determination of molecular weight is needed to decide which multiple of the empirical formula represents the molecular formula.
The empirical formula for the compound X3Y12 is X1Y4. This is determined by dividing the subscripts by the greatest common factor, which in this case is 3 for X and 12 for Y.
The empirical formula of a compound with the molecular formula C12H8 is CH2. This is determined by dividing the subscripts in the molecular formula by the greatest common factor (in this case, 4) to obtain the simplest whole-number ratio of atoms in the compound.
The empirical formula NH2Cl has a molar mass of 51.5 g/mol, so the molecular formula can be determined by finding the ratio of the molar mass of the molecular formula to the molar mass of the empirical formula. The molecular formula of the compound is therefore NH2Cl2.
The empirical formula for B3N3H6 is BNH2. This is determined by dividing all subscripts by the greatest common factor, which is 3 in this case.
The empirical formula of Na2S2O4 is NaSO2. This is determined by dividing the subscripts in the molecular formula by their greatest common factor to obtain the simplest whole-number ratio of atoms present in the compound.
It is an empirical formula.