The dissociation equation for aluminum chloride (AlCl₃) in water (H₂O) can be represented as follows:
[ \text{AlCl}_3 (s) \rightarrow \text{Al}^{3+} (aq) + 3 \text{Cl}^- (aq) ]
This equation shows that one formula unit of AlCl₃ dissociates into one aluminum ion (Al³⁺) and three chloride ions (Cl⁻) when dissolved in water.
The equation for the dissociation of water is: H2O ↔ H+ + OH-
The equation is: H2O------>H+ + OH-
The dissociation equation for aluminum chloride (AlCl₃) in water is as follows: [ \text{AlCl}_3 (s) \rightarrow \text{Al}^{3+} (aq) + 3 \text{Cl}^- (aq) ] When AlCl₃ dissolves in water, it separates into aluminum ions (Al³⁺) and chloride ions (Cl⁻), resulting in an aqueous solution.
AlCl3 & H2O AlCl3 & H2O Solving Al2O3 (s) in HCl Al2O3 (s) + 6 HCl (aq) → 2 [AlCl3] (s, aq*) + 3 H2O (l) *depending on amount of acid used. Excessive amounts of acid will solve the formed AlCl3 (s) into 2([Al3+][Cl-]3) (aq)
The dissociation equation for zinc fluoride (ZnF2) in water is: ZnF2 (s) → Zn2+ (aq) + 2F- (aq)
The equation for the dissociation of water is: H2O ↔ H+ + OH-
hnc7h4so3 + h2o --> nc7h4so3- + h3o
The reaction is:FeS2 + H2O + 3,5 O2 --------------- FeSO4 + H2SO4It is not a dissociation reaction.
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
The equation is: H2O------>H+ + OH-
The equation is: H2O------>H+ + OH-
The dissociation is:NaHCO3-------------Na+ + (HCO3)-
The dissociation of water molecules into hydrogen ions and hydroxide ions is best represented by the equation: H2O -> H+ + OH-.
There is no reaction. Alcohol and water just mix together, like in beer, wine, or liquor.
The dissociation of 2 protons from trihydrogen phosphate (H3PO4) results in the formation of dihydrogen phosphate (H2PO4-) and a water molecule (H2O). The chemical equation for this process can be written as: H3PO4 ⇌ H2PO4- + H+ + H2O
The balanced equation for the dissociation of lauric acid (C12H24O2) in water is: C12H24O2(s) + H2O(l) → C12H25O2^-(aq) + H3O+(aq)
The dissociation equation for aluminum chloride (AlCl₃) in water is as follows: [ \text{AlCl}_3 (s) \rightarrow \text{Al}^{3+} (aq) + 3 \text{Cl}^- (aq) ] When AlCl₃ dissolves in water, it separates into aluminum ions (Al³⁺) and chloride ions (Cl⁻), resulting in an aqueous solution.