The f1 and f2 factors are metrics used to assess the similarity between two dissolution profiles in pharmaceutical studies. The f1 factor (dissimilarity) quantifies the percentage difference between the two profiles, while the f2 factor (similarity) measures the logarithmic mean of the absolute differences between the two profiles. An f2 value greater than 50 typically indicates that the profiles are similar, while f1 values closer to zero suggest similarity. These factors help in evaluating the bioequivalence of drug formulations.
when two notes of frequencies f1 and f2 after sound together, beasts are formed. If f1>f2 what will be the frequency of beasts
F1 and F2
When a first object exerts a force, F1 ,on a second object, the second object simultaneously exerts a force, F2 = −F1 on the first object. This means that F1 and F2 are equal in magnitude and opposite in direction.
If two F1 members are crossed, their offspring will be known as an F2 generation. The traits of the F2 generation can vary based on the genes inherited from their F1 parents through a process called genetic recombination. This can lead to new combinations of traits not present in the original F1 parents.
F1 Generation
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when two notes of frequencies f1 and f2 after sound together, beasts are formed. If f1>f2 what will be the frequency of beasts
Suppose the perfect number P has divisors f1, f2, ... , fk, P (where all the fs are smaller than P. Then, by the definition of a perfect number, f1 + f2 + ... + fk = P So that f1 + f2 + ... + fk + P = 2P Dividing through by P, f1/P + f2/P + ... + fk/P + P/P = 2 . . . . . . . . . . . (2) Now, since f1 is a factor of P, the f1*g1 = P where g is the cofactor and so f1/P = 1/g1. That is, f1/P is the reciprocal of one of the other factors of P. Also, the last term on the left is the reciprocal of the factor 1. And therefore, f1/P + f2/P + ... + fk/P + P/P = 2 = 1/g1 + 1/g2 + ... + 1/gk + 1/1
<html> <head> <title>asp</title> </head> <% dim f1,f2,f3,c f1=0 f2=1 response.Write(f1 &"<br>") response.write(f2 &"<br>") c=1 while(c<=10) f3=f1+f2 response.write(f3 &"<br>") c=c+1 f1=f2 f2=f3 wend %> </html>
S2 + F1 - F2 = F1 + b2
F1=normal force F2=gravitational force on the bulb net force=F1+F2 but f1 and f2 are same in magnitude but differ in direction.(newton 3rd law of motion) If we add both f1 and f2,they will cancel out Therefore ; The net force=f1+(-f2)=0 So,the net force on the bulb is 0N
Net force is just the summation of forces, if the forces are in same direction net force will be Fnet = F1+F2 ,and if they travel in opposite direction Fnet = F1 + (-F2) or F1-F2
S2 + F1 - F2 = F1 + b2
Following logic for Fibonocci int f1=0; intf2=1; int i=0; while(i
Infinitely many ways. Suppose you have found a way of writing the given fraction, F, as a sum of two fractions, f1 and f2.Take any other fraction g such that g < f1 and g is not equal to the absolute value of f1 - f2. Then consider (f1 - g) and (f2 + g). Since f1, f2 and g are all fractions, then so are (f1 - g) and (f2 + g). And their sum is F.
int f1=1, f2=1, c=2; do { t=f1+f2; printf("%d\t",t); f1=f2; f2=t; c=c+1; }while(c
If the value changes from fraction1 (F1) to fraction 2 (F2), then the percentage change is 100*(F2/F1 - 1) provided F1 > 0. If F1 is 0 then the value is not defined, and if F1 <0 you get nonsense results.