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The impulse or the momentum

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11y ago

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What is Change in momentum times time?

Impulse = [(change in momentum)/time]*time[(change in momentum)/time] = ForceAnd when force acts for a period of time, that impulse changes the momentum of the object.You can also rewrite the impulse equation as: I = F*tHowever, for change in momentum times time, the units would be (kg*m/s)*(s) = kg*m. These units are not in common usage.


What are the dimensions of the force f knowing that f is equal to the mass m times the acceleration a?

[ force ] = [ mass ] [ acceleration ] = [ mass ] [ length/time2 ] = [ mass-length-time-2 ]


When a force is applied over a period of time if you increase the time the force is applied then the amount of force does what?

When a force is applied over a longer period of time, the total impulse delivered to an object increases, which can result in a greater change in momentum. However, the amount of force itself does not inherently change; it remains constant unless otherwise altered. Instead, increasing the time allows the same force to have a greater effect on the object's velocity or motion. Thus, while the force remains the same, the cumulative effect on the object is enhanced with longer application times.


What is the dimension of force if density and frequency and acceleration due to gravity are the bare quantities?

Frequency and density aren't involved as 'bare quantities' in force. The bare quantities that constitute force are mass, length, and time, and the physical dimension of force is (mass) x (length)/(time)2 . The 'length' and 'time' combine to result in (length)/(time)2, and that's the 'acceleration' that you did include.


What does force divided by distance equal?

Work is force times distance. A Force divided by Distance: looking at the units, Force = newtons = kg m / s^2 = mass x length / time^2 so ML/T^2 Distance = m = length so L Force/Distance = (ML/T^2)/L = ML/LT^2 = M/T^2 So the units of a force divided by distance are mass/ time^2 This would be the rate of change of mass change with respect to time.