Hydrazine. Keep up the hard work!
HNNH has the stronger nitrogen-nitrogen bond compared to H2NNH2. This is because HNNH is a diazene molecule, which has a triple bond between the nitrogen atoms, while H2NNH2 is hydrazine, with a single bond between the nitrogen atoms. Triple bonds are stronger than single bonds.
HNNH has the shorter nitrogen-nitrogen bond because it has a triple bond between the nitrogen atoms, which is shorter and stronger than the single bond in H2NNH2.
There are two lone pairs of electrons in the Lewis structure of hydrazine (H2NNH2), one on each nitrogen atom. These lone pairs contribute to the molecule's overall geometry and reactivity.
HNNHThe first compound(H2NNH2) has a single bong between the nitrogen atoms and follows the octet rule allowing nitrogen's orbital to hold 8 electrons. The second compound (HNNH) requires nitrogen to be double bonded. Double bonds are stronger than single bonds.Source:Yahoo Answers
I think: H2CCH2 H H | | C_C | | H H H2NNH2: H-H-:N-N:-H-H Two Nitrogen atoms connected by single bond with a lone pair and 2 Hydrogen atoms at each ends
No, H2NNH2 is not an Arrhenius base because it is a weak base known as hydrazine. Arrhenius bases dissociate in water to produce hydroxide ions (OH-), whereas hydrazine does not ionize to form OH- ions but rather accepts protons (H+).
The N-N bond in H2NNH2 (hydrazine) is stronger than in HNNH (diazene). This is because hydrazine has a longer N-N bond length, allowing for more electron-electron repulsion, which strengthens the bond. Diazene has a shorter N-N bond with less electron-electron repulsion, resulting in a weaker bond.
Bases, with partial negative charges and overshielded nuclei, grab protòns from watter. In azo molecules, lone elèctronic pairs on the nitrogen are these negative ends. ammonia: H3N + H2O → H4N+ + HO− hydrazine hydrate: H2NNH2·nH2O + H2O → H2NHNH2+ + n H2O + HO−
oxidation value of each N atom in hydrazine (H2NNH2) is -2 and in NO3- it is +5(standard in compounds: H is +1, O is -2, but these stay unchanged)The difference in oxidation value is (-2) -(+5) = -7 = 7 electrons (e-) per N atom (or 14 e- per 2N's in one N2H4).So 7 electrons are to be donated to - (and taken or accepted by) one NO3- ion.oxidator: 2NO3- + 16 H+ + 14 e- --> N2H4 + 6 H2Oreductor (donator): XXX --> YYY + 14 e-
The bond in N2 dinitrogen is a triple bond, with a length of 109.76 pm. An indicator of the length of a single N-N bond is given by hydrazine. H2NNH2, where the N-N is 145pm, this indicates the shortening in N2 due to the extra pi bonds.