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At sample of 131 I decays to 1.0 grams in 40 days. What was the mass of the original sample?
To determine the original mass of the iodine-131 sample, we can use the radioactive decay formula, which states that the remaining mass can be calculated using the equation ( N(t) = N_0 e^{-\lambda t} ). Given that the sample decays to 1.0 grams in 40 days, and knowing the half-life of iodine-131 is approximately 8 days, we can calculate the decay constant and then find the original mass ( N_0 ). After performing the calculations, the original mass of the iodine-131 sample was approximately 5.6 grams.
Why reduced mass is smaller than its original mass?
Reduced mass takes into account the contribution of both bodies in a system, whereas the original mass considers only one of the bodies. By considering the relative motion between two bodies in a system, the reduced mass usually ends up being smaller than the original mass.
How many moles of carbon C were in the original sample?
To determine the number of moles of carbon in the original sample, you need to know the mass of carbon present and its molar mass, which is approximately 12.01 g/mol. You can calculate the number of moles using the formula: moles = mass (g) / molar mass (g/mol). If you have the mass of carbon from the sample, simply divide that value by 12.01 g/mol to find the number of moles.
Why density is the criteria for purity with respect to chemistry?
Mass and volume are extensive properties, which are dependent upon the size of the sample. A larger sample will have a greater mass and volume than a smaller sample. Density is an intensive property, which does not depend on the size of the sample. Density is a ratio of mass to volume, which does not vary with the size of the sample. The density of a larger sample will be the same as the density of a smaller sample.
What is the mass (by difference) of a sample if the initial mass of the sample in the bottle was 28.81-g and the final mass of the bottle and sample was 21.33-g?
7.48
At sample of 131 I decays to 1.0 grams in 40 days. What was the mass of the original sample?
To determine the original mass of the iodine-131 sample, we can use the radioactive decay formula, which states that the remaining mass can be calculated using the equation ( N(t) = N_0 e^{-\lambda t} ). Given that the sample decays to 1.0 grams in 40 days, and knowing the half-life of iodine-131 is approximately 8 days, we can calculate the decay constant and then find the original mass ( N_0 ). After performing the calculations, the original mass of the iodine-131 sample was approximately 5.6 grams.
Why reduced mass is smaller than its original mass?
Reduced mass takes into account the contribution of both bodies in a system, whereas the original mass considers only one of the bodies. By considering the relative motion between two bodies in a system, the reduced mass usually ends up being smaller than the original mass.
How many moles of carbon C were in the original sample?
To determine the number of moles of carbon in the original sample, you need to know the mass of carbon present and its molar mass, which is approximately 12.01 g/mol. You can calculate the number of moles using the formula: moles = mass (g) / molar mass (g/mol). If you have the mass of carbon from the sample, simply divide that value by 12.01 g/mol to find the number of moles.
Why density is the criteria for purity with respect to chemistry?
Mass and volume are extensive properties, which are dependent upon the size of the sample. A larger sample will have a greater mass and volume than a smaller sample. Density is an intensive property, which does not depend on the size of the sample. Density is a ratio of mass to volume, which does not vary with the size of the sample. The density of a larger sample will be the same as the density of a smaller sample.
Why does a chain reaction die out in small pieces of fissionable fuel but not in large pieces?
Because in small samples the probability of a neutron escaping the sample without inducing another fission is bigger. Actually, what matters is the mass of the sample, especially if this mass exceeds the critical mass. Thus, the chain reaction in a smaller sample with sufficiently higher density of fissionable material might not die out, while it dies out in a larger sample with albeit a sufficiently smaller density of fissionable material.
Why is now mass spectroscopy used instead of radiocarbon dating?
Mass spectrometry has not replaced radiocarbon dating, it is used as a better way to measure the amount of carbon-14 in the sample that permits smaller sample sizes and improved accuracy.
What is the mass (by difference) of a sample if the initial mass of the sample in the bottle was 28.81-g and the final mass of the bottle and sample was 21.33-g?
7.48
If 12.5 grams of the original sample of cesium-137 remained after 90.69 years what was the mass of the original sample?
To find the original mass of the cesium-137 sample, you can use the exponential decay formula: final amount = initial amount * (1/2)^(time/half-life). With the information provided, you would have: 12.5 = initial amount * (1/2)^(90.69/30.1). Solving for the initial amount gives you approximately 40 grams.
What advantages does mass spectrometry have over nuclear magnetic resonance spectrometry?
Mass spectrometry can analyze samples quicker, has a higher sensitivity, and can conduct analysis with smaller sample volumes.
How to find the percent by mass of a compound in a given sample?
To find the percent by mass of a compound in a given sample, you need to divide the mass of the compound by the total mass of the sample and then multiply by 100. This will give you the percentage of the compound in the sample.
'A large rock is weathered into tiny pieces which add up to the weight of the original rock This demonstrates the conservation of?
This scenario demonstrates the conservation of mass. Weathering breaks down the rock into smaller pieces, but the total mass of the smaller pieces remains equal to the original rock.
A 20.0 mL sample of CuSO4 was evaporated to dryness leaving 0.967g of residue What was the molarity of the original solution?
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
