In studying the process of the sterility assurance level, which is how you guarantee the sterility of a sample of bacterium, each log reduction assures that 90% of the sample is sterile, so log 6 reduction just ensures it further.
After t hours the number of bacteria is 10*2t. So 10*2t > 3000000 => 2t > 300000 => t(log2) > log(300000) => t > log(300000)/(log2) => t > 18.19.. So in just over 18 hours (or 18 hours and 12 minutes, approx).
Insects, slime molds, worms, bacteria, protists, nematodes
Bacteria grow most rapidly during the log phase.
Yes because the log was once a part of a tree tree's are biotic
Is "log" and "lag" one and the same?The answer is definitely NO!One common mistake of a ranatic is using log instead of lag...The difference between the two relies under its respective meanings:LOG: a written record of messages sent or received / log - treeLAG: the act of slowing down or falling behindIf you are referring to the delay in-game, it's LAG.If you are entering the game (eg. typing your username and password), you are creating a LOG.
log(x) - log(6) = log(15)Add log(6) to each side:log(x) = log(15) + log(6) = log(15 times 6)x = 15 times 6x = 90
log(x6) = log(x) + log(6) = 0.7782*log(x) log(x6) = 6*log(x)
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
log(x) + 4 - log(6) = 1 so log(x) + 4 + log(1/6) = 1 Take exponents to the base 10 and remember that 10log(x) = x: x * 104 * 1/6 = 10 x = 6/1000 or 0.006
It really depends on the bacteria. Some multiply best at room temperature, some at 60 deg celcius. Bacteria has 4 phases in life. The lag, log/exponential, stationary or the death phase. Bacteria multiply best at its log phase. The log phase depends on the bacteria species.
The graph of ( \log(x) + 6 ) is a vertical translation of the graph of ( \log(x) ) upwards by 6 units. This means that every point on the graph of ( \log(x) ) is shifted straight up by 6 units, while the shape and orientation of the graph remain unchanged. The domain of the function remains the same, which is ( x > 0 ).
You have, y = 6 + log x anti log of it, 10y = (106) x
logx +7=1+log(x-1) 6=log(x-1)-logx 6=log[(x-1)/x] 10^6=(x-1)/x 1,000,000x=x-1 999,999x=-1 x=-1/999,999
-6
bacteria
To enter a natural log, press the LN button. To enter a log with base 10, press the LOG button. To enter a log with a base other than those, divide the log of the number with the log of the base, so log6(8) would be log(8)/log(6) or ln(8)/ln(6). (The ln is preferred because in calculus it is easier to work with.)
The pH of a solution can be calculated using the formula pH = -log[H+]. Substituting the given H+ concentration (3.7x10-6) into the formula gives pH = -log(3.7x10-6) ≈ 5.43. Therefore, the pH of the solution is approximately 5.43.