The combining ratio of potassium and bromine is 1:1, meaning that one atom of potassium combines with one atom of bromine to form potassium bromide (KBr).
An iodine atom has one more principal energy level than a bromine atom. Therefore the radius of an iodine atom is greater than the latter.
There are two atoms in one molecule KBr. One atom of potassium (K) and one atom of bromine (Br).
A bromine atom has 7 half-filled orbitals: one in the 4s orbital, three in the 4p orbitals, and three in the 4d orbitals.
A bromine atom normally has 35 protons. With a charge of -1, it means one electron has been gained, making it 36 protons and 36 electrons.
The chemical formula for the compound containing one carbon atom for every four bromine atoms is CBr4, known as carbon tetrabromide.
The ratio of magnesium bromide (MgBr₂) consists of one magnesium (Mg) atom to two bromine (Br) atoms. This means that for every one magnesium atom, there are two bromine atoms, resulting in a 1:2 ratio. In the compound, the subscript '2' indicates that there are two bromine atoms for each magnesium atom.
The official IUPAC name for this compound is tetrabromomethane, but more American chemists probably call it "carbon tetrabromide".
The combining ratio of potassium and iodine is 1:1, meaning one atom of potassium will combine with one atom of iodine. The combining ratio of bromine and iodine is 1:1 as well, indicating that one atom of bromine will combine with one atom of iodine.
The chemical formula for silver bromide is AgBr. It is composed of one atom of silver (Ag) and one atom of bromine (Br).
The compound described is bromine nitride chloride, with the chemical formula Br2NCl.
The combining ratio of potassium and bromine is 1:1, meaning that one atom of potassium combines with one atom of bromine to form potassium bromide (KBr).
NClBr2 although I'm pretty sure there is no such compound.
lose only one electron
The Lewis structure for CBr2O includes one carbon atom bonded to two bromine atoms and one oxygen atom. The carbon atom is in the center, with one double bond to oxygen and two single bonds to bromine. Each bromine and oxygen atom is surrounded by a lone pair of electrons.
The formula for bromine heptafluoride is BrF7, which consists of one bromine atom and seven fluorine atoms.
An iodine atom has one more principal energy level than a bromine atom. Therefore the radius of an iodine atom is greater than the latter.