I tried to dissolve AgNO3 in DMF and i found that it is easily soluble in it . So one can have a try, distilled water can also be best employed for the same .
AgNO3 powder is white but a little grey solid.
The silver nitrate solution (AgNO3) provides the silver in silver chloride.
Its name is silver nitrate octahydrate. silver(Ag) nitrite(NO2) * octahydrate (8H2O)
0.688 moles*6.02x1023=4.14x1023 Formula units
AgNO3
The chemical formula for silver nitrate is AgNO3.
The chemical formula for silver nitrate is AgNO3.
mass (g) solute divided by total mass (g)times 100%total mass (g) = [mass solute + mass (g) solvent]54.0 / [128 + 54.0] = 29.6%
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
AgNO3 powder is white but a little grey solid.
To find the number of moles, you need to divide the given mass (85 grams) by the molar mass of AgNO3 (169.87 g/mol). 85 grams of AgNO3 represents 0.500 moles.
The correct formula for silver (I) nitrate is AgNO3.
Silver nitrate (AgNO3) is composed of 63.5% silver by mass.
The chemical formula of silver nitrate is AgNO3.
(NH4)NO3 + AgNO3 --> (NH4)NO3 + AgNO3
Silver nitrate is the chemical name for the molecular compound having formula AgNO3. It is composed of silver (Ag) and a nitrate group (NO3). The reaction for its disassociation into water (H2O) is:AgNO3(s) + H20(l) <--> Ag+ (aq) + NO3-(aq) + H2O(l)