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What is the Kinetic Energy of the trolley at the top of the ramp if a trolley of mass is 25Kg and is released from the top of a ramp which stands at a height of 3m?

Mass = 25 Kg

Height = 3 m

This is an energy problem. At the top of the ramp, the trolley is at rest and 3m above the base line.

Potential Energy = Weight * height

Weight = mass * acceleration due to gravity

Acceleration due to gravity = 9.8m/s^2

Potential Energy = 25 kg * 9.8m/s^2 * 3 m

Potential Energy = 735 Joules

When the trolley reaches the bottom of the ramp, all the potential energy has been converted to Kinetic energy.

Potential Energy = 735 Joules = Kinetic energy

Kinetic energy = ½ * mass * velocity^2

Kinetic energy = ½ * 25 * V^2 = 735 multiply 735 by 2 and divide by 25

V^2 = 58.8

V = 7.67 m/s

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