The anion in SnBr4 is bromide (Br⁻). In this compound, tin (Sn) has a +4 oxidation state, and each bromine atom contributes a -1 charge, resulting in a total of four bromide anions to balance the charge of the tin cation. Therefore, SnBr4 consists of one tin cation and four bromide anions.
The cation for SnBr4 is Sn^4+, which is the tin(IV) cation.
These compounds are tin bromides: SnBr2, SnBr4.
The correct stock name for SnBr4 is tin(IV) bromide. In this compound, tin has a +4 oxidation state, indicated by the Roman numeral IV, while bromide ions carry a -1 charge. Therefore, four bromide ions are needed to balance the +4 charge of the tin ion.
Cl -As this is a negatively charged ion it is a anion.
anion
The ionic compound SnBr4 is named tin(IV) bromide.
The cation for SnBr4 is Sn^4+, which is the tin(IV) cation.
The old name of the formula SnBr4 is tin(IV) bromide.
These compounds are tin bromides: SnBr2, SnBr4.
The ionic compound SnBr4 is called tin (IV) bromide. It consists of tin cations with a +4 charge and bromide anions with a -1 charge.
Yes Tin Bromide - I use it at work
polyatomic anion
The anion in sulphates is the SO42-.
Cl -As this is a negatively charged ion it is a anion.
Anion
anion
The anion of chlorine is chloride (Cl-).