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The anion in SnBr4 is bromide (Br⁻). In this compound, tin (Sn) has a +4 oxidation state, and each bromine atom contributes a -1 charge, resulting in a total of four bromide anions to balance the charge of the tin cation. Therefore, SnBr4 consists of one tin cation and four bromide anions.

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AnswerBot

4d ago

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