i have no clue
The chemical equation is:6 CH3COOAg + Al2(SO4)3 = 3 Ag2SO4 + 2 Al(CH3COO)3
Aluminium sulfate is soluble in water; no reaction occur.
The balanced chemical equation for the reaction between tartaric acid and copper sulfate is: C4H6O6 + 3CuSO4 -> Cu3(C4H4O6)2 + 3SO4.
The chemical formula that contains aluminum ions and tetraoxosulfate is ( \text{Al}_2(\text{SO}_4)_3 ). In this compound, aluminum ions (( \text{Al}^{3+} )) are combined with sulfate ions (( \text{SO}_4^{2-} )), resulting in a neutral compound where two aluminum ions balance with three sulfate ions. This is commonly known as aluminum sulfate.
When aluminum (Al) reacts with iron(II) sulfate (FeSO4), aluminum sulfate (Al2(SO4)3) and iron (Fe) are produced. This reaction is a displacement reaction where aluminum displaces iron from the sulfate compound to form aluminum sulfate and elemental iron.
The balanced equation for the reaction between aluminum and copper(II) sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
The word equation for aluminum sulfate is: aluminum sulfate + water → aluminum hydroxide + sulfuric acid.
2Al + 3CuSO4 = Al2(SO4)3 + 3Cu
The balanced chemical equation for the reaction between aluminum and copper sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
No, epsom salt, which is magnesium sulfate, or MgSO4 that is hydrated (MgSO4·7H2O), is chemically different from aluminum acetate. The latter has several forms, including aluminum monoacetate, (HO)2AlC2H3O2, aluminum diacetate, HOAl(C2H3O2)2, and aluminum triacetate, Al(C2H3O2)3. Links are provided below to check facts and learn more.
This is a double replacement reaction which would look like this: 2NH4C2H3O2 + CaSO4 yields (NH4)2SO4 + Ca(C2H3O2)2 so the products are (NH4)2SO4, which is ammonium sulfate, and Ca(C2H3O2)2, which is calcium acetate. These are both soluble in water, so the reaction will reverse itself until it reaches equilibrium, usually indicated by an arrow pointed in either direction in the equation (if you have to balance the equation too).
The chemical equation for the reaction when copper is added to aluminum sulfate is: 3Cu + 2Al2(SO4)3 -> 3CuSO4 + 2Al
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
The net ionic equation for mixing sodium acetate and ammonium sulfate solutions would be: 2CH3COO- (aq) + (NH4)2SO4 (aq) -> 2CH3COOH (aq) + (NH4)2SO4 (aq) Overall, the reaction results in the formation of acetic acid and ammonium sulfate.
Step 1: Na1+ + SO42- = Na2SO4 (you nees to balance out the charges of sodium and sulfate individually. Then you combine them and you get sodium sulfate.) Step 2: 2Na1+ + SO42-= Na2SO4 (Now the whole equation is balanced :) you have 2Na on the left to balance the 2Na on the right and SO4 is equal on both left and right side with a 1:1 molar ratio.
The chemical equation for the reaction between aluminum sulfate and calcium hydroxide is: Al2(SO4)3 + 3Ca(OH)2 -> 3CaSO4 + 2Al(OH)3
The reaction equation for hydrogen sulfate (H2SO4) and aluminum hydroxide (Al(OH)3) is: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O