one out of four or 25% for monohybrid ratio
It depends on the parents. The parent could have two dominant genes which would give a 0% chance of the offspring being recessive. The only way that the offspring could have a recessive characteristic is if the both parents have one dominant and one recessive gene, a 25% chance. The chance that both parents would pass on the recessive gene (if they have one dominant and recessive gene) is also 25%, because there is a 50% chance for each parent.
Their offspring will have dominant genes. However, if these offspring have offspring with an amimal with recessive genes, the recessive genes will show up.
hh X Hh You get two recessives; hh and hh and two heterozygous plants; Hh and Hh
A disorder can be either dominant or recessive, depending on the specific genetic inheritance pattern. Dominant disorders only require one copy of the mutated gene to be expressed, while recessive disorders require two copies.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
Yes, the offspring has a 50% chance of being polled. The polled gene is dominant over the horned gene, so if the bull does not carry the horned gene, the offspring will not have horns.
If 75 offspring have a Dominant gene, then the parents must have at least one Dominant gene each. This would make them either Dominant Homozygous (DD) or Heterozygous (Dd) for the Dominant trait.
It depends on the parents. The parent could have two dominant genes which would give a 0% chance of the offspring being recessive. The only way that the offspring could have a recessive characteristic is if the both parents have one dominant and one recessive gene, a 25% chance. The chance that both parents would pass on the recessive gene (if they have one dominant and recessive gene) is also 25%, because there is a 50% chance for each parent.
When a recessive and dominant gene mix, the dominant gene will typically determine the trait expressed in the offspring. This is known as dominant inheritance, where the dominant gene masks the presence of the recessive gene in determining the phenotype.
Their offspring will have dominant genes. However, if these offspring have offspring with an amimal with recessive genes, the recessive genes will show up.
Transmitted by a dominant gene. If that gene is inherited from either parent, the offspring will develop HD. If the gene is NOT inherited, then the offspring will not have HD- AND cannot pass the gene to their offspring.
To have offspring with black fur, both parent dogs must carry the gene for black fur. This gene is usually dominant, meaning that if at least one parent carries it, there's a high chance the offspring will have black fur. If both parents have black fur, then their offspring will also have black fur.
The likelihood that the offspring of individuals IV-3 and IV-4 will inherit the trait depends on the specific genetic inheritance pattern of the trait. If the trait is determined by a dominant gene, there is a 50 chance that the offspring will inherit the trait. If the trait is determined by a recessive gene, there is a 25 chance that the offspring will inherit the trait.
for what animal. it all depends on the dominant gene (allele) and recessive. the genotype of the parents needs to be set up in a Punnett square and with that data you can determine the probability that an animal will have brown fur
More information is needed. The percent of offspring that will display the recessive trait from parents with Hh and HH will be different than the percent of offspring that will display the recessive trait from parents with hh and Hh.
Since the mother would be considered a carrier, the gene will be produced in the offspring. the son will receive that gene and will be colorblind.
when the traits are dominant and are passed down to the offspring.