By charge, I assume you mean oxidation number. Oxygen's oxidation number is a very dependable -2, with only a few strange exceptions. A better question would be "What is chlorine's oxidation number in ClO4-?" The answer would be +7.
The compound Ca(CLO4)2 is called calcium perchlorate. It consists of calcium ions (Ca²⁺) and perchlorate ions (ClO4⁻). In this formula, there are two perchlorate ions for each calcium ion, reflecting the need for charge balance in the compound.
ClO4 is polar.
3 moles of (ClO4)3- and 1 mol AlAluminium perchlorate is Al)CLO4)3.10H2O.
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CIO4- is nothing. The conjugate acid of ClO4- (with a lowercase L) is HClO4, perchloric acid
The answer is Cd(ClO4)2 The charge of cadmium(II) is 2+, and the charge of ClO4 is 1-. So to even the charges we must have two of the ClO4.
The oxidation state of Mn in Mn(ClO4)3 is +7. This is because the overall charge of the perchlorate ion (ClO4)- is -1, and there are 3 perchlorate ions in Mn(ClO4)3, resulting in a total charge of -3. To balance this, the Mn ion must have an oxidation state of +7.
The oxidation number of each oxygen atom in ClO4- is -2. Since there are 4 oxygen atoms in ClO4-, and the total charge of the ion is -1, the oxidation number of oxygen must be adjusted to achieve the net charge, giving an oxidation number of +6 for the central chlorine atom.
The compound Ca(CLO4)2 is called calcium perchlorate. It consists of calcium ions (Ca²⁺) and perchlorate ions (ClO4⁻). In this formula, there are two perchlorate ions for each calcium ion, reflecting the need for charge balance in the compound.
The oxidation number of chlorine in ClO4 is +7. Each oxygen atom has an oxidation number of -2 and the overall charge of the ion is -1, which means the oxidation number of chlorine must be +7 to balance the charge.
Ba(ClO4)2 is an ionic compound. Ba (Barium) is a metal, whereas ClO4 (perchlorate) is a polyatomic ion that carries a negative charge. In ionic compounds, metals typically donate electrons to nonmetals to form ions that are held together by electrostatic forces.
Perchlorate ion (ClO4-) is colorless.
Cu(ClO4)2 dissociates into Cu2+ ions and 2 ClO4- ions in solution. This results in the breakdown of the copper perchlorate compound into its constituent ions when dissolved in water. The balanced equation for the dissociation of Cu(ClO4)2 is: Cu(ClO4)2 -> Cu2+ + 2 ClO4-.
The formula for magnesium perchlorate is Mg(ClO4)2.
The chemical symbol for perchlorate is ClO4-.
The oxidation number of Cl in ClO4- is +7. This is because oxygen usually has an oxidation number of -2 and there are four oxygen atoms in ClO4-, giving a total of -8. Since the overall charge of the ion is -1, the oxidation number of Cl must be +7 to balance the charges.
The oxidation number of each oxygen atom in the perchlorate ion (ClO4-) is -2. Since the overall charge of the ion is -1, the oxidation number of chlorine must be +7 to balance out the negative charges from the oxygens.