The formula for tin(II) fluoride is SnF₂. In this compound, tin has a +2 oxidation state, while each fluoride ion has a -1 charge. Therefore, two fluoride ions are needed to balance the charge of one tin ion, resulting in the formula SnF₂.
Pb10S10 The prefix deca in decasulfide means that there are 10 sulfide ions in the formula, each with a 2- charge. So the total negative charge is 10 x 2-, which equals 20-. To balance the total sulfide charge, you need enough lead II ions to equal 20+, so that means 10 lead II ions, which equals a charge of 20+. This is not really the correct way to name this compound. It should just simply be lead II sulfide, and the proper formula would be PbS, which, if you look at the ratio of lead to sulfide ions, which is 10:10, the formula for lead II decasulfide should be reduced to PbS.
Iron(II) sulfide is insoluble in water.
Chromium (ii) sulfide
NiS is the formula for nickel sulfide. The nickel(II) ion has a 2+ charge and the sulfide ion is 2-. When the Ni(II)2+ bonds with the S2- the 2s cancel out and you are left with NiS (nickel sulfide). E. Morris
The chemical formula for tin (IV) sulfide is SnS2.The chemical formula for tin (II) sulfide is SnS.
The chemical formula for tin(II) sulfide is SnS.
The formula for copper(II) sulfide is CuS the formula for copper(I) sulfide is Cu2S.
Tin(II) sulfide is a chemical compound of tin and sulfur. Its chemical formula is SnS.
*Tin Sulfate* NO! This is WRONG!SnS2 is Tin(IV) Sulfide, not Tin SulfateThe (IV) means that Tin has a 4+ charge (can be Tin(II) with a 2+ charge or Tin(IV))Sulfur has a 2- charge, so it takes 2 Sulfur ions to balance out the chargesso you have 1 Tin Ion with a charge of 4+ and 2 Sulfur Ions with charges of 2+put them together and it makes SnS2Sulfate is a polyatomic ion with the formula SO4 with a 2- charge, so the formula for Tin Sulfate would be Sn(SO4)2
When you add sodium sulfide to tin chloride, a precipitation reaction occurs which forms tin sulfide, NaCl, and Na2SO4. Tin sulfide is a solid that precipitates out of solution.
The name for Sn2S4 is tin(IV) sulfide or stannic sulfide.
The formula for platinum (II) sulfide is PtS. The platinum (II) ion has a charge of 2+ and the sulfide ion has a charge of 2-. Therefore, in order to form a neutral compound, one platinum (II) ion combines with one sulfide ion.
BeS is an ionic compound called beryllium sulfide. It is composed of beryllium (Be) cations and sulfide (S) anions. Beryllium has a +2 charge, while sulfide has a -2 charge, leading to a neutral compound.
Sn(CLO3)2 Tin (II) has a positive 2 charge and Chlorate has a (-1) charge so you need to cholrates to one Tin.
The formula for tin(II) fluoride is SnF₂. In this compound, tin has a +2 oxidation state, while each fluoride ion has a -1 charge. Therefore, two fluoride ions are needed to balance the charge of one tin ion, resulting in the formula SnF₂.
The ionic compound formed between Pb2+ and S2- ions is lead(II) sulfide, with the chemical formula PbS. Lead(II) has a 2+ charge while sulfide has a 2- charge, making the compound electrically neutral.