There really isn't an exact chemical formula. Oxidation simply means the loss of an electron!
The chemical formula for copper II oxide is CuO. It is a black solid compound where copper is in the +2 oxidation state.
The oxidation of magnesium is a process, and as such has a chemical equation rather than a formula: 2 Mg + O2 -> 2 MgO. MgO is the chemical formula for the oxide of magnesium.
The chemical formula of cupric oxide is CuO.
A pure metal has the oxidation state zero.
Ba3N2 Nitride has an oxidation state of -3 ( N3- ) and Barium has an oxidation state of +2, or Ba2+. To obtain the formula, the charges are balanced out and the result is an oxidation state of 0. The formal is Ba3N2.
Oxidation
Formula: BrN Br in 3+ oxidation state
For the one oxidation state. HgNO3 for the two oxidation state. Hg(NO3)2
With the 2 oxidation state. NiCO3
It indicates the oxidation state.
Cobalt has many oxidation states.Commonly fomula can be CoF2.
The manganese(IV) selenide has the chemical formula MnSe2.
The chemical formula depends on the specific ions mentioned. Without knowing the ions, we cannot determine the formula or oxidation numbers. Can you provide the ions you are referring to?
In a molecule the oxidation number is written in ROMAN numerals after the given element. Although all Group oxidise, any one Group only oxidises by the Group Number, except the Transition Element. These lie between Group '2' & '3' in the Periodic Table. If we take say, potassium permanganate (KMnO4) The manganese (Mn) has different oxidation states. In the above molecule KMnO4 we could write it as KMn(VII)O4. The potassium(K) is a Group '1' element so its oxidation state is Always '1'. The oxygen (O) has a standard at '-2' . So for four oxygens the overall moiety on oxygen is 4 x -2 = -8 Composing a little sum Mn + 1 - 8 = 0 (Zero for a neutrally charged molecule). We have Mn = 8 - 1 = (+)7 (Roman Numerals VII). The oxidation Number tells us that seven of the manganese electrons in the outer electron energy shell take part in bonding. Compare to nitrogen in Ammonia (NH3) Nitrogen has five electrons in its outer energy (valance) shell , but only three of those five electrons are involved in bonding to hydrogens, leaving a 'lone pair' of unbonded electrons in nitrogen of ammonia. So nitrogen's oxid'n state in ammonia is '+3'. Archaically, there is a subtle change of name to indicate different oxidation states. e.g. Ferrous chloride (Fe(II)Cl2 Ferric chloride (Fe(III)Cl3 However, remember that Oxidation Number refers to the number of electrons in the outer energy(valance) shell that are involved in Bonding.
TiO
The chemical formula for potassium metaperiodate is KIO4. The oxidation number of potassium is +1.
Oxidation numbers help determine the ratio of elements in a compound, which is essential for writing a correct chemical formula. They allow you to balance the charges of the ions or atoms present to ensure overall charge neutrality in the compound. Additionally, oxidation numbers give insight into the transfer of electrons during chemical reactions.