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In a 0.25 M solution of aluminum carbonate, Al2(CO3)3, the compound dissociates into its ions: 2 aluminum ions (Al³⁺) and 3 carbonate ions (CO3²⁻) for each formula unit. Thus, from one mole of Al2(CO3)3, you get 2 moles of Al³⁺ and 3 moles of CO3²⁻. Therefore, in a 0.25 M solution, the concentration of Al³⁺ ions is 0.50 M (2 x 0.25 M) and the concentration of CO3²⁻ ions is 0.75 M (3 x 0.25 M).

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AnswerBot

2mo ago

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