To find the current drawn by a 60-watt fluorescent lamp, you can use the formula: current (I) = power (P) / voltage (V). Assuming the lamp operates at a standard voltage of 120 volts, the current would be approximately 0.5 amps (60W / 120V = 0.5A). If the lamp operates at a different voltage, simply adjust the calculation accordingly.
For a 60W lamp, a normal fuse rating would be around 3A. This is calculated using the formula P = V x I, where P is power, V is voltage, and I is current. So for a 60W lamp on a 120V circuit, you would use a 3A fuse to safely handle the power load.
Typically, if the ballast on a fluorescent light blows, the lamp will not work. The ballast regulates the electrical current to the lamp, so if it is not functioning properly, the lamp will not receive the correct power to light up.
NO. Two 60W lamps will use 120W - which is more than 100W !!
The choke is used to limit the current flowing through the fluorescent lamp during start-up, allowing the lamp to warm up gradually. The starter is responsible for providing the initial high-voltage kick needed to start the lamp by ionizing the gas inside the tube. Together, the choke and starter work to regulate the flow of electricity and provide the necessary conditions for the fluorescent lamp to operate efficiently.
No, incandescent lamp dimmers are not compatible with fluorescent lamps. Fluorescent lamps require special dimming ballasts to control their light output. Attempting to use an incandescent lamp dimmer with a fluorescent lamp can cause damage to the lamp and dimmer.
reynold harina
For a 60W lamp, a normal fuse rating would be around 3A. This is calculated using the formula P = V x I, where P is power, V is voltage, and I is current. So for a 60W lamp on a 120V circuit, you would use a 3A fuse to safely handle the power load.
Yes, lamp is to fluorescent
Typically, if the ballast on a fluorescent light blows, the lamp will not work. The ballast regulates the electrical current to the lamp, so if it is not functioning properly, the lamp will not receive the correct power to light up.
NO. Two 60W lamps will use 120W - which is more than 100W !!
Thomas Alva Edison invented fluorescent lamp in 1896
P=VI so I=P/V I= 60/230 I=0.261 A
The choke is used to limit the current flowing through the fluorescent lamp during start-up, allowing the lamp to warm up gradually. The starter is responsible for providing the initial high-voltage kick needed to start the lamp by ionizing the gas inside the tube. Together, the choke and starter work to regulate the flow of electricity and provide the necessary conditions for the fluorescent lamp to operate efficiently.
No, incandescent lamp dimmers are not compatible with fluorescent lamps. Fluorescent lamps require special dimming ballasts to control their light output. Attempting to use an incandescent lamp dimmer with a fluorescent lamp can cause damage to the lamp and dimmer.
The average price of a fluorescent desk lamp is about $30. You can buy a fluorescent lamp for as much as $55, or as little as $17. It depends on the brand size of bulbs used in the lamp.
Since power is volts time amps, the current in a 60W lamp connected to 120V is 0.5A. Since a lamp is a resistive load, there is no need to consider power factor and phase angle, so that simplifies the explanation. ======================== Assuming this is an incandescent or halogen lamp (using a filament to make the light) there is a trick here: the resistance of a lamp filament varies with temperature and does not follow Ohm's law. The resistance will be much lower, thus the current will be much higher when the filament is cold, when the lamp is first connected. As the filament heats up, the resistance increases until it gets to a steady operating point of 0.5A. For a halogen lamp, the operating temperature is about 2800-3400K, so the R at room temperature is about 16 times lower than when hot... so when connected, the current is about 8A but drops rapidly. The current could be even higher if the lamp is in a cold environment. Non-halogen lamps operate at a lower temperature and would have a lower initial current--about 5A. And this all assumes the lamp is rated for 120V. If it is a 12V/60W lamp, the filament will probably break and create an arc, which may draw a very large current.
The capacitor in a fluorescent lamp is primarily used to improve the power factor of the lamp's circuit. It helps to correct the phase difference between the voltage and current in the circuit, which can improve the overall efficiency of the lamp. Additionally, the capacitor helps to stabilize the voltage across the lamp, reducing flickering and ensuring a more consistent light output.