The electron configuration of copper(II) is [Ar] 3d9 . Copper is [Ar] 3d10 4s1
The electron configuration for the +2 cation of cobalt (Co) is [Ar] 3d7. This is because cobalt has an atomic number of 27, which means its neutral configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d7. When it forms a +2 cation, it loses two electrons from its 4s subshell, resulting in the configuration [Ar] 3d7.
It has 39 electrons and ends in a d orbital. Now finish your homework :)
Beryllium electron configuration is [He]2s2.
The noble gas configuration of lead is [Xe] 4f^145d^106s^26p^2. Lead's electron configuration can be abbreviated using the nearest noble gas, which in this case is xenon.
The electron configuration for neutral Barium is [Xe] 6s2. Barium plus 2 means it has lost 2 electrons, so the electron configuration for Barium plus 2 would be [Xe].
Cobalt electron configuration is [Ar]3d7.4s2.Cobalt(2+) electron configuration is [Ar]3d7.
The electron configuration of copper(II) is [Ar] 3d9 . Copper is [Ar] 3d10 4s1
The electron configuration of lead (Pb) is [Xe] 4f^14 5d^10 6s^2 6p^2, where [Xe] represents the electron configuration of xenon, which is the noble gas before lead in the periodic table. Lead has 82 electrons in total.
The electron configuration for the +2 cation of cobalt (Co) is [Ar] 3d7. This is because cobalt has an atomic number of 27, which means its neutral configuration is 1s2 2s2 2p6 3s2 3p6 4s2 3d7. When it forms a +2 cation, it loses two electrons from its 4s subshell, resulting in the configuration [Ar] 3d7.
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
The electron configuration of sulfur (long) is: 1s22s22p63s23p4. The electron configuration of sulfur (short) is: [He]3s23p4.
The longhand electron configuration for sulfur is 1s2.2s2.2p6.3s2.3p4.
The electronic configuration of tin is: [Kr]D10.5s2.5p2.The electronic configuration of chromium(2+) is correct.
There is no element such as 12M. Assuming that you mean 12Mg, the electron configuration is 2, 8, 2.
It has 39 electrons and ends in a d orbital. Now finish your homework :)
The short electron configuration for carbon is [He] 2s^2 2p^2.