It is a Metal Ion of copper.
CUSO was created in 1961.
To determine the limiting reagent between CuSO₄ and NaOH, we first need to look at the balanced chemical equation for the reaction, which is: [ CuSO₄ + 2 NaOH \rightarrow Cu(OH)₂ + Na₂SO₄ ] According to the stoichiometry, 1 mole of CuSO₄ reacts with 2 moles of NaOH. First, calculate the moles of CuSO₄ and NaOH. Assuming the molar mass of CuSO₄ is approximately 159.61 g/mol, 638.44 g of CuSO₄ corresponds to about 4.00 moles. For 240.0 g of NaOH (molar mass ≈ 40.00 g/mol), this is about 6.00 moles. Since 4.00 moles of CuSO₄ would require 8.00 moles of NaOH but only 6.00 moles are available, NaOH is the limiting reagent.
To determine how many grams of CuSO₄ are required, we first need to calculate the moles of KI. With 300.0 mL of 0.75 mol/L KI, the moles of KI are 0.300 L × 0.75 mol/L = 0.225 moles. Assuming a 1:1 reaction ratio (which is typical for reactions between KI and CuSO₄), 0.225 moles of CuSO₄ are needed. The molar mass of CuSO₄ is approximately 159.61 g/mol, so the mass required is 0.225 moles × 159.61 g/mol = 35.9 grams of CuSO₄.
Copper sulfate (CuSO₄) contains copper (Cu) in the +2 oxidation state. In this state, copper has an electron configuration of [Ar] 3d⁹, resulting in one unpaired electron in the 3d subshell. Therefore, the expected number of unpaired electrons in CuSO₄ is one.
A single-replacement reaction occurs when an element replaces another element in a compound. For example, if zinc (Zn) is placed in a solution of copper sulfate (CuSO₄), it will replace copper, resulting in the formation of zinc sulfate (ZnSO₄) and copper metal (Cu). The reaction will only occur if the replacing element is more reactive than the element being replaced. Therefore, to determine if a single-replacement reaction will occur, one must compare the reactivities of the involved elements using the activity series.
CUSO was created in 1961.
CUSO-VSO was created in 1961.
He is a bakugan player and leader of bakugan battle brawlers,his element is pyrus (fire),He is number 1 bakugan player. By:Nic
The answer is stoeker whale!
CuSO 4
To determine the limiting reagent between CuSO₄ and NaOH, we first need to look at the balanced chemical equation for the reaction, which is: [ CuSO₄ + 2 NaOH \rightarrow Cu(OH)₂ + Na₂SO₄ ] According to the stoichiometry, 1 mole of CuSO₄ reacts with 2 moles of NaOH. First, calculate the moles of CuSO₄ and NaOH. Assuming the molar mass of CuSO₄ is approximately 159.61 g/mol, 638.44 g of CuSO₄ corresponds to about 4.00 moles. For 240.0 g of NaOH (molar mass ≈ 40.00 g/mol), this is about 6.00 moles. Since 4.00 moles of CuSO₄ would require 8.00 moles of NaOH but only 6.00 moles are available, NaOH is the limiting reagent.
To determine how many grams of CuSO₄ are required, we first need to calculate the moles of KI. With 300.0 mL of 0.75 mol/L KI, the moles of KI are 0.300 L × 0.75 mol/L = 0.225 moles. Assuming a 1:1 reaction ratio (which is typical for reactions between KI and CuSO₄), 0.225 moles of CuSO₄ are needed. The molar mass of CuSO₄ is approximately 159.61 g/mol, so the mass required is 0.225 moles × 159.61 g/mol = 35.9 grams of CuSO₄.
how should anyone know? maybe albert ienstien
CuSO₄+2NaOH=Na₂SO₄+Cu(OH)₂↓
Copper sulfate (CuSO₄) contains copper (Cu) in the +2 oxidation state. In this state, copper has an electron configuration of [Ar] 3d⁹, resulting in one unpaired electron in the 3d subshell. Therefore, the expected number of unpaired electrons in CuSO₄ is one.
A single-replacement reaction occurs when an element replaces another element in a compound. For example, if zinc (Zn) is placed in a solution of copper sulfate (CuSO₄), it will replace copper, resulting in the formation of zinc sulfate (ZnSO₄) and copper metal (Cu). The reaction will only occur if the replacing element is more reactive than the element being replaced. Therefore, to determine if a single-replacement reaction will occur, one must compare the reactivities of the involved elements using the activity series.
20)=5.18=90(g)