It is a Metal Ion of copper.
CUSO was created in 1961.
To determine the limiting reagent between CuSO₄ and NaOH, we first need to look at the balanced chemical equation for the reaction, which is: [ CuSO₄ + 2 NaOH \rightarrow Cu(OH)₂ + Na₂SO₄ ] According to the stoichiometry, 1 mole of CuSO₄ reacts with 2 moles of NaOH. First, calculate the moles of CuSO₄ and NaOH. Assuming the molar mass of CuSO₄ is approximately 159.61 g/mol, 638.44 g of CuSO₄ corresponds to about 4.00 moles. For 240.0 g of NaOH (molar mass ≈ 40.00 g/mol), this is about 6.00 moles. Since 4.00 moles of CuSO₄ would require 8.00 moles of NaOH but only 6.00 moles are available, NaOH is the limiting reagent.
To determine how many grams of CuSO₄ are required, we first need to calculate the moles of KI. With 300.0 mL of 0.75 mol/L KI, the moles of KI are 0.300 L × 0.75 mol/L = 0.225 moles. Assuming a 1:1 reaction ratio (which is typical for reactions between KI and CuSO₄), 0.225 moles of CuSO₄ are needed. The molar mass of CuSO₄ is approximately 159.61 g/mol, so the mass required is 0.225 moles × 159.61 g/mol = 35.9 grams of CuSO₄.
A single-replacement reaction occurs when an element replaces another element in a compound. For example, if zinc (Zn) is placed in a solution of copper sulfate (CuSO₄), it will replace copper, resulting in the formation of zinc sulfate (ZnSO₄) and copper metal (Cu). The reaction will only occur if the replacing element is more reactive than the element being replaced. Therefore, to determine if a single-replacement reaction will occur, one must compare the reactivities of the involved elements using the activity series.
When iron (Fe) reacts with copper(II) sulfate (CuSO₄), a single displacement reaction occurs. In this reaction, iron displaces copper, resulting in the formation of iron(II) sulfate (FeSO₄) and elemental copper (Cu). The overall reaction can be represented as: [ \text{Fe} + \text{CuSO}_4 \rightarrow \text{FeSO}_4 + \text{Cu} ] Thus, the products formed are iron(II) sulfate and copper.
CUSO was created in 1961.
CUSO-VSO was created in 1961.
He is a bakugan player and leader of bakugan battle brawlers,his element is pyrus (fire),He is number 1 bakugan player. By:Nic
The answer is stoeker whale!
CuSO 4
how should anyone know? maybe albert ienstien
CuSO₄+2NaOH=Na₂SO₄+Cu(OH)₂↓
20)=5.18=90(g)
When iron (Fe) reacts with copper(II) sulfate (CuSO₄), a single displacement reaction occurs. In this reaction, iron displaces copper, resulting in the formation of iron(II) sulfate (FeSO₄) and elemental copper (Cu). The overall reaction can be represented as: [ \text{Fe} + \text{CuSO}_4 \rightarrow \text{FeSO}_4 + \text{Cu} ] Thus, the products formed are iron(II) sulfate and copper.
There is no CuSO. If you mean CuSO4, it would be 6 atoms per formula unit; one Cu atom, one S atom, and 4 O atoms.
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To find the molar mass of copper (II) sulfate pentahydrate, calculate the individual molar masses of each element present (Cu, S, O, and H) from the periodic table, and then multiply by the respective subscript in the formula. Add up the molar masses of copper (II) sulfate (CuSO₄) and five water molecules (5H₂O) to get the molar mass of copper (II) sulfate pentahydrate.