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What is the Empirical formula of the compound that is 52.7 percent K 47.3 percent Cl?

The empirical formula of the compound with 52.7% K and 47.3% Cl is KCl (potassium chloride). This is because the ratio of potassium to chlorine atoms in the compound is 1:1, leading to the simple formula KCl.


How does one determine a percent composition from an empiricle formula?

To determine the percent composition from an empirical formula, first calculate the molar mass of the compound by summing the atomic masses of all the elements in the formula. Next, for each element, divide its total mass in the empirical formula by the molar mass of the compound and multiply by 100 to get the percent composition. This process gives the percentage of each element in the compound relative to the total mass.


Can the empirical formula be used to calculate the percent composition of a compound?

Yes, the empirical formula can be used to determine the percent composition of a compound. The percent composition can be calculated by determining the molar mass of each element in the formula and then dividing the molar mass of each element by the molar mass of the whole compound, and finally multiplying by 100 to get the percent composition.


What does one determine a percent composition from an empirical formula?

To determine the percent composition from an empirical formula, first calculate the molar mass of the compound by summing the atomic masses of all the elements in the formula. Then, for each element, divide its total mass in the formula by the compound's molar mass and multiply by 100 to get the percentage. This process provides the proportion of each element in the compound relative to the total mass.


An unknown sample with a molecular mass of 180.0g is analyzed to yield 40 percent C 6.7 percent H and 53.3 percent O What is the empirical formula and the molecular formula of this compound?

The empirical formula is CH2O. To find the molecular formula, you need to calculate the empirical formula weight (30 g/mol) and divide the molecular mass (180.0 g/mol) by the empirical formula weight to get 6. This means the molecular formula is (CH2O)6, which simplifies to C6H12O6, the molecular formula of glucose.

Related Questions

What is the empirical formula of a compound that contains 20 percent calcium and 80 percent bromine by mass?

The empirical formula would be CaBr2 since it contains a ratio of 1 calcium to 2 bromine atoms.


Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?

The empirical formula of this compound would be MgO.


What is the empirical formula of a compound that contains 32.39 percent sodium 22.53 percent sulfur and 45.07 oxygen?

The empirical formula of the compound is Na2SO4, which is sodium sulfate. This is because the percentages given closely correspond to the molar ratios in the compound, with a sodium to sulfur to oxygen ratio of 2:1:4.


How do you know when to solve for a empirical formula?

You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.


Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?

Chi a+


A compound used to test for the presence of ozone in the stratosphere contains 96.2 percent thallium and 3.77 percent oxygen What is its empirical formula?

The molar mass of the compound is 444.8 g/mol. To find the empirical formula, we need to determine the number of moles of each element in the compound. The molar ratio of thallium to oxygen is approximately 3:1, so the empirical formula is TlO3.


What is the percent composition of a compound with the empirical formula CO2?

The percent composition of a compound with the empirical formula CO2 is 27.3% carbon and 72.7% oxygen.


Calculate the empirical formula of a compound formed from 3 percent c 3 percent h and 96 7 percent you which formula below correctly represents the empirical formula?

CHI3


What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?

p2o5


What is the empirical formula of a compound that contains 53.73 percent Fe and 46.27 percent of S?

The empirical formula of the compound containing 53.73% Fe and 46.27% S is FeS. This is determined by dividing the given percentages by the molar mass of each element to find the mole ratio, which simplifies to FeS in this case.


What is the empirical formula of a compound that is 40 percent sulfure and 60 percent oxygen?

The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.


What is the empirical formula for a compound that is 43.6 percent and 56.4 percent oxygen?

The empirical formula for the compound that is 43.6% carbon and 56.4% oxygen is CO2. This is because the ratio of carbon to oxygen in carbon dioxide is 1:2.