What is the energy of an electromagnetic wave with the frequency of 8E12 Hz?

Answer 1

1.99 10-24 j

Answer 2

E = hf, where E is energy in Joules, h is Planck's constant, 6.626 x 10-34 J•s, and f is frequency in /s or Hz.

E = (6.626 x 10-34J•s)(8 x 1012 Hz) = 5 x 10-21J

Answer 3

5.3 x 10 ^ -21 J

Answer 4

The energy in the beam depends on whatever source is generating it.

We can calculate the energy in each photon of that electromagnetic wave,
but that doesn't tell us how many photons are pouring out of the source.

The energy in each photon is (Planck's Konstant) x (Frequency)

Planck's Konstant = 6.63 x 10-34 joule-sec

Energy in each photon = (6.63 x 10-34 joule-sec) x (3,109 per second) = 2.061 x 10-30 joule

If the source produces 1 trillion trillion of those every second, then the power
pouring out of the source is 0.000002061 watt.

A blinding beam, to be sure. But I'm not worried, because I happen to know that
in order to radiate electromagnetic energy with reasonable efficiency, you'll need
a dipole antenna that's 1/2 wavelength long, and with my innate knack for figures,
I quickly realize that at 3,109 Hz, a half-wavelength is 96 Km (59.92 miles), so it's
doubtful that you'll be on the air and radiating with that puppy for some time.

Answer 5

f = E/h, where f is frequency, E is energy, and h is Planck's constant, 6.626 × 10-34 J.s.

If frequency is known, you can find E by manipulating the equation such that E = f x h = (3 x 109Hz)(6.626 × 10-34 J.s) = 2 x 10-24J.

Answer 6

.5.3 10-21 j

Answer 7

E ≡ hf = 6·6E-34 J s 8E12 Hz = 5·3E-21 J.