What is the final temperature of a mixture of 85 g of 80 C and 85g of 40 C of water?

Answer 1

To find the final temperature of the mixture, we can use the principle of conservation of energy, where the heat lost by the hot water equals the heat gained by the cold water. Since both masses are equal (85 g) and using the specific heat capacity of water, the final temperature ( T_f ) can be calculated as follows:

[ T_f = \frac{(m_1 \cdot T_1) + (m_2 \cdot T_2)}{m_1 + m_2} ] [ T_f = \frac{(85 , \text{g} \cdot 80 , \text{C}) + (85 , \text{g} \cdot 40 , \text{C})}{85 , \text{g} + 85 , \text{g}} = \frac{6800 + 3400}{170} = \frac{10200}{170} = 60 , \text{C} ]

Thus, the final temperature of the mixture is 60 °C.