example 51 = 1/2 5 v2
so 51 / (1/2 5) = your squared
51 / (2.5) = 20.4
square root of 20.4 is your velocity
hope this helps, can say if it's 100% correct but i tried to work this out myself and haven't got it wrong yet after a few trials
try it on this one, simply remove the allready know 18 (v)...
your answer should equal what the v2 equals, then square root that number for velocityEk = (1/2 80) (182) = 12960
Yes, it is possible to change the translational kinetic energy of an object without changing its rotational energy. Translational kinetic energy depends on an object's linear velocity, while rotational energy depends on its angular velocity. By adjusting the linear velocity without changing the angular velocity, you can change the object's translational kinetic energy without affecting its rotational energy.
The answer to both of your questions lies in the different nature of both quantities, momentum and kinetic energy. Momentum is a vector, kinetic energy is a scalar. This means that momentum has a magnitude and a direction, while kinetic energy just has a magnitude. Consider the following system: 2 balls with equal mass are rolling with the same speed to each other. Magnitude of their velocities is the same, but the directions of their velocities are opposed. What can we say about the total momentum of this system of two balls? The total momentum is the sum of the momentum of each ball. Since masses are equal, magnitudes of velocities are equal, but direction of motion is opposed, the total momentum of the system of two balls equals zero. Conclusion: the system has zero momentum. What can we say about the total kinetic energy of this system? Since the kinetic energy does not take into account the direction of the motion, and since both balls are moving, the kinetic energy of the system will be different from zero and equals to the scalar sum of the kinetic energies of both balls. Conclusion: we have a system with zero momentum, but non-zero kinetic energy. Assume now that we lower the magnitude of the velocity of one of the balls, but keep the direction of motion. The result is that we lower the total kinetic energy of the system, since one of the balls has less kinetic energy than before. When we look to the total momentum of the new system, we observe that the system has gained netto momentum. The momentum of the first ball does not longer neutralize the momentum of the second ball, since the magnitudes of both velocities are not longer equal. Conclusion: the second system has less kinetic energy than the first, but has more momentum. If we go back from system 2 to system 1 we have an example of having more kinetic energy, but less momentum. I hope this answers your question Kjell
If an object is rolling without slipping, then its kinetic energy can be expressed as the sum of the translational kinetic energy of its center of mass plus the rotational kinetic energy about the center of mass. The angular velocity is of course related to the linear velocity of the center of mass, so the energy can be expressed in terms of either of them as the problem dictates, such as in the rolling of an object down an incline. Note that the moment of inertia used must be the moment of inertia about the center of mass. If it is known about some other axis, then theparallel axis theorem may be used to obtain the needed moment of inertia.
Depends on what is between the potential difference (ie, the voltage). If it's an evaculated tube, and the electrons are travelling between the anode and the cathode without much interference, then then a higher voltage will mean that the electrons arrive with more kinetic energy -- ie, increased velocity. However, if there's a wire between the two voltages, then the drift velocity of the electrons (which is pretty slow to begin with) does not increase, but only the number of electrons that are drifting.
"Escape velocity" is a misnomer; there isn't any such thing. "Escape velocity" is the speed that it would take a projectile to escape completely from the Earth's gravity, IF IT WERE FIRED FROM THE SURFACE FROM A CANNON.The "escape velocity" from Earth is about 7 miles per second, or 25,000 miles per hour. But the Apollo spacecraft that went to the Moon didn't go anywhere near that speed. It didn't have to, because it was propelled by a rocket engine. With a big enough engine and enough fuel, you could "escape" from the Earth at 5 miles per hour, or less. It would be TERRIBLY wasteful of fuel, which is why we don't do it that way.
One can determine kinetic energy without knowing the velocity by using the formula: Kinetic Energy 0.5 x mass x velocity2. This formula allows for the calculation of kinetic energy based on the mass of the object and its velocity.
Momentum is the product of mass and velocity. Kinetic Energy is the product of mass and velocity squared. As you can see, since Kinetic Energy is derived from mass and velocity, and Momentum is derived from mass and velocity, you cannot have one without the other.
Yes, it is possible to change the translational kinetic energy of an object without changing its rotational energy. Translational kinetic energy depends on an object's linear velocity, while rotational energy depends on its angular velocity. By adjusting the linear velocity without changing the angular velocity, you can change the object's translational kinetic energy without affecting its rotational energy.
The kinetic energy of a steel object at 10°C can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the steel object and v is its velocity. Without the velocity of the steel object, we cannot calculate its kinetic energy. Temperature alone does not provide enough information.
The kinetic energy of a rolling ball is the energy it possesses due to its motion. It is calculated using the formula KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the ball, and v is the velocity of the ball. When a ball is rolling, it has both translational and rotational kinetic energy, which can be calculated separately and then added together to find the total kinetic energy of the ball.
The kinetic energy of the disc can be calculated using the formula: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the disc, and v is the velocity. Plugging in the values: KE = 0.5 * 2 kg * (4 m/s)^2 = 16 J. So, the kinetic energy of the disc is 16 Joules.
Kinetic energy is equal to one-half of the product of an object's mass and the square of its velocity. Velocity is change in displacement divided by time. If you have the kinetic energy and mass, you can calculate the velocity by taking the square root of the quotient of kinetic energy and mass, and thereby solving for the velocity.
kinematic is the study of state of motion of a body i.e. includes both rest and moving bodies.. but kinetic is study of moving bodies only.... study means calculating velocity, accelration..etc..
momentum = mass * velocity kinetic energy = 1/2 mass * velocity^2 If an object has non-zero momentum, it has non-zero velocity. It thus has kinetic energy, at least. It most likely has other forms of energy as well (potential, thermal, etc.)
Momentum = (mass) x (speed) Kinetic Energy = 1/2 (mass) x (speed)2 It looks like the only way a body can have zero momentum is to have either zero mass or else zero speed, and if either of those is zero, then that makes the KE also zero as well, too. So the answer to the question is apparently: no.
That can't be answered without the question but kinetic energy (KE) can be calculated like this: KE = 0.5mv2, where m is mass (kg) and v is velocity (m/s)
KE=1/2MV^2 Or in other words, Kinetic Energy = 0.5 x Mass (1000g) x Velocity (measured in metres per second) Squared (make sure you only square the Velocity) For example if your 1kg ball was going at 2 metres per second, then the equation would look like this: KE = 0.5 x 1000 x 4 = 2000 Joules