magnesium iodide
It is a ionic compound. It is made out by Ni and i2.
Yes.
No, like all potassium compounds potassium iodide is ionic.
Strontium iodide (SrI2) is a salt of strontium and iodine. It is an ionic, water-soluble, and deliquescent compound that can be used in medicine as a substitute for potassium iodide Strontium iodide (SrI2) is a salt of strontium and iodine. It is an ionic, water-soluble, and deliquescent compound that can be used in medicine as a substitute for potassium iodide
The ionic formula for boron iodide is B2I6.
Formula: I-
The formula for the ionic compound of potassium and iodide is KI, where K represents potassium and I represents iodide. Potassium is a group 1 element with a +1 charge, while iodide is a halogen with a -1 charge, resulting in a balanced 1:1 ratio in the compound.
The formula for the ionic compound formed from ammonium and iodide ions is NH4I. Ammonium ion has a charge of +1 and iodide ion has a charge of -1, so they combine in a 1:1 ratio to form a neutral compound.
The ionic compound of sodium iodide is NaI. It is composed of sodium (Na+) ions and iodide (I-) ions held together by ionic bonds.
Depends on if you have iron (II) iodide or iron (III) iodide. iron (II) iodide is FeI2, while iron (III) iodide is FeI3.
The formula unit for sodium iodide is NaI. This compound is made up of sodium cations (Na+) and iodide anions (I-), which combine in a 1:1 ratio to form a neutral compound.
Potassium iodide is ionic.
CsI.... it's not just a hit TV show, its an ionic compound as well.
The formula for cesium iodide is CsI, where Cs is the chemical symbol for cesium and I is the chemical symbol for iodide. It is an ionic compound composed of cesium cations (Cs+) and iodide anions (I-).
No, RbI is not an ionic compound. It is a binary ionic compound consisting of rubidium and iodine ions held together by ionic bonds.
The formula for the ionic compound formed between Boron and Bromine is BBr3. Boron loses three electrons to achieve a stable octet, while Bromine gains one electron to achieve a stable octet, forming a compound with a 3:1 ratio.