The equation for half-life is ...
AT = A0 2(-T/H)
... where A0 is the starting activity, AT is the ending activity at some time T, and H is the half-life in units of T.
Given that A0 is 1, H is 27 seconds, and T is 86400 seconds (one day, or 24 hours), AT is simply 5.06x10-964.
This sounds a bit extreme, and perhaps the question was mis-stated, but that's what the equation produces.
Yes, but it has a halflife of only 0.86 seconds.
In order to have an equation, we need to know what isotope of neon we are dealing with. Neon 2 is not an isotope.
THE QUESTION IS INVALID. THE HALF-LIFE OF FLUORINE-20 is 11.07 SECONDS. There will be about 0.92 of of an isotope with a half-life of 114 seconds remaining after 14 seconds. The equation for half-life decay is AT = A0 2(-T/H) where T is time and H is half-life. 2(-14/114) is equal to about 0.92. In the case of fluorine-20, 2(-14/11.07) is about 0.42.
To calculate QTcB (corrected QT interval using Bazett's formula) without the RR interval, you can use the formula QTcB = QT / √(RR), where QT is the measured QT interval in seconds. If the RR interval is not available, you can estimate it using the heart rate: RR = 60 / heart rate (in bpm). Then, plug this value into the formula to obtain the corrected QT interval.
Based on the formula, P = E/T , and 5 min is 300 seconds, 100 = E/300, E = 30000
To calculate acceleration between 6 and 9 seconds, you need to find the change in velocity during that time interval and then divide it by the time taken. The formula for acceleration is acceleration = (final velocity - initial velocity) / time. Plug in the velocities at 6 seconds and 9 seconds into the formula to get the acceleration.
The formula to calculate the car's average acceleration between 0 and 2.1 seconds is: Average acceleration (final velocity - initial velocity) / time interval This formula gives the acceleration in meters per second squared (m/s).
You can't convert between seconds, and meters/second. If you have a problem that involves speeds, use the formula: distance = speed x time.
Yes, but it has a halflife of only 0.86 seconds.
To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
In order to have an equation, we need to know what isotope of neon we are dealing with. Neon 2 is not an isotope.
Isotope A is more radioactive because it has a shorter half-life, indicating a faster rate of decay. A shorter half-life means that more of the isotope will undergo radioactive decay in a given time period compared to an isotope with a longer half-life.
MPH = miles per hour. In order to calculate hours from seconds, you just need to know that there are 3,600 seconds in an hour.
Seconds/3600 = Hours
(4 coulombs / 2 seconds) = 2 coulombs per second = 2 Amperes.
You must convert the mass from pounds to kilograms, time from seconds to seconds, and distance from feet to meters. Only then can you use the formula for momentum (momentum = mass * velocity) to calculate momentum in SI units (kg*m/s).
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