National Assessment and Accreditation Council
Concentration sodium acetate (C(NaAc)) solution with pH = 9.05 will have to be 0.21 mol/L NaAc, while pK(NaAc) = 9.23Calculate with these formula: [OH-] = SQRT[K(NaAc) * C(NaAc)] soC(NaAc) = [OH-]2 / K(NaAc) = 0.21 mol/L NaAcin which [OH-] = 10(-14 + 9.05) = 10-4.95 = 1.12*10-5and K(NaAc) = 10-9.23 = 5.89*10-10
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Concentration sodium acetate (C(NaAc)) solution with pH = 9.05 will have to be 0.21 mol/L NaAc, while pK(NaAc) = 9.23Calculate with these formula: [OH-] = SQRT[K(NaAc) * C(NaAc)] soC(NaAc) = [OH-]2 / K(NaAc) = 0.21 mol/L NaAcin which [OH-] = 10(-14 + 9.05) = 10-4.95 = 1.12*10-5and K(NaAc) = 10-9.23 = 5.89*10-10
No, NaAc (sodium acetate) is not a base. It is the salt of acetic acid. Sodium acetate is a weak base that can act as a buffer in solutions.
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