What is the half-life of the reaction C2H6(g) and rarr2CH3(g)?

Answer 1

The half-life of the reaction ( \text{C}_2\text{H}6(g) \rightarrow 2\text{CH}3(g) ) depends on the order of the reaction. For a first-order reaction, the half-life is constant and can be calculated using the formula ( t{1/2} = \frac{0.693}{k} ), where ( k ) is the rate constant. If the reaction is second-order, the half-life depends on the initial concentration, calculated using ( t{1/2} = \frac{1}{k[\text{C}_2\text{H}_6]^0} ). Thus, without specific rate constants or concentration values, the exact half-life cannot be determined.