The phenotypic ratio expected from a monohybrid cross between heterozygotes is 3:1 (assuming complete dominance), with the genotypic ratio being 1:2:1.
So, using tall = T, short = t and R = red, r = white as an example.
A monohybrid cross of Tt X Tt would be expected to produce 3 tall plants and 1 short plant (phenotypic ratio 3:1), which would be 1 TT, 2 Tt and 1 tt (genotypic ratio 1:2:1).
A dihybrid cross of heterozygotes is expected to produce a phenotypic ratio of 9:3:3:1.
So the cross of TtRr X TtRr would be epected to have:
9 tall red, 3 tall white, 3 short red and 1 short white (phenotypic ratio)
This is because each parent has 4 possible combinations of gametes (TR, Tr, tR and tr). There are therefore 16 combinations of gametes, providing a 9:3:3:1 phenotypic ratio.
Both of these are probably best visualised using a punnett square (see link below).
A 9:3:3:1 phenotypic ratio is characteristic of a dihybrid cross where two genes are segregating independently and assorting according to Mendel's law of independent assortment. This ratio is expected when the genes are located on different chromosomes or are far apart on the same chromosome.
The Young and the Restless - 1973 1-9331 was released on: USA: 8 February 2010
Days of Our Lives - 1965 1-9331 was released on: USA: 19 June 2002
9331/1000
There are 9331 miles between Fayetteville NC and Noosa Australia.
The phone number of the Bayliss Public Library is: 906-632-9331.
The phone number of the Hector Maclean Public Library is: 910-628-9331.
The phone number of the Jim Gatchell Museum Of The West is: 307-684-9331.
The phone number of the Flatiron Building Heritage Center is: 724-785-9331.
The phone number of the Helen Kate Furness Fr Library is: 610-566-9331.
The 9/3/3/1 ration is the ratio of phenotypes that are the result of a dihybrid cross. Consider two genes, A and B, that reside on different chromosomes (so that they independently assort). Assume each gene has two alleles. For A, A is dominant and a is recessive, while for the B gene, B is dominant and b is recessive. Now consider a cross between two individuals that are heterozygous for both genes (this is called a dihybrid cross): AaBb X AaBb There are only 4 possible gametes that each individual can produce (in equal proportion): AB Ab aB ab So if we cross the two we get 16 combinations. This will result in 9 possible genotypes: AABB AABb AAbb AaBB AaBb Aabb aaBB aaBb aabb However, there are only 4 possible phenotypes (with proportion in parentheses): Dominant A and B (9/16) (AABB, AABb, AaBB, AaBb) Dominant A, Recessive B (3/16) (AAbb, Aabb) Recessive A, Dominant B (3/16) (aaBB, aaBb) Recessive A, Recessive B (1/16) (aabb)
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