What is the index of refraction of a solid in which the speed of light is 1.943x10 rise to the power of 8mins per secs?

Answer 1

The index of refraction (n) of a medium can be calculated using the formula ( n = \frac{c}{v} ), where ( c ) is the speed of light in a vacuum (approximately ( 3.00 \times 10^8 ) m/s) and ( v ) is the speed of light in the medium. Given that the speed of light in the solid is ( v = 1.943 \times 10^8 ) m/s, the index of refraction can be calculated as follows:

[ n = \frac{3.00 \times 10^8 , \text{m/s}}{1.943 \times 10^8 , \text{m/s}} \approx 1.54. ]

Thus, the index of refraction of the solid is approximately 1.54.