The inner radius of the stratosphere is about 10 kilometers, while the outer radius extends up to 50 kilometers. The volume of the stratosphere can be estimated by using the formula for the volume of a cylinder, since the stratosphere can be approximated as a cylindrical shape.
No. The combined thickness of the inner and outer core is about 3500 to 3520 kilometers, out of the Earth's total radius of about 6370 kilometers. This means that the combination of inner solid core and liquid outer core has about 16% of the Earth's volume. *The reference to "1% of the Earth's volume" may refer to the Earth's crust, which has about "1% of the Earth's total mass."
Remembering that there is an inner core inside the outer core - the radius of the outer core/mantle boundary is about 3,400 km. (the diameter is twice the radius).
The inner radius is 6 cm, and the outer radius is 9 cm. The circumference of a circle is given by the formula C = 2πr. Therefore, the inner circumference is 2π(6) = 12π cm, and the outer circumference is 2π(9) = 18π cm. The difference between the outer and inner circumferences is 18π - 12π = 6π cm.
The core consists of an inner solid core with a radius of 760 miles, and an outer liquid core with a total diameter of 1400 miles. Applying the 4/3pi(r3) volume formula to these values we get: 1.8 billion cubic miles for the solid core and 11.7 billion cubic miles for the total outer and inner core volume. This compares to a total volume for the earth of 32.5 billion cubic miles.
The crust occupies less than 1% of Earth's volume.
pi(r2)of inner minus pi(r2) of outer. multiply height= volume or you could drop it in a beaker and see how much water was displaced
Outer volume = pi*142*40 cm3 Inner volume = pi*122*40 cm3 Volume of steel = Outer volume - Inner volume = pi*(142 - 122)*40 cm3 = pi*52*40 = 6535 cm3 approx.
4/3 * pi * (125 - 27)Improved answer with the same result:If the outer circumference is 10 times pi cm then its outer radius is 5 cm and its inner radius is 3 cm.outer volume - inner volume = volume of the sphere's shell(4/3*pi*53) - (4/3*pi*33) = 410.5014401 or 410.5 cubic cm to 1 decimal place
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
Surface area of a sphere = 4*pi*radius2 For a spherical shell, surface area = surface area of outer sphere - surface area of inner sphere = 4*pi*(outer radius)2 - 4*pi*(inner radius)2 = 4*pi*[ (outer radius)2 - (inner radius)2 ]
==================================Answer #2:I believe you want the volume of the shell ... the material between theinside and outside diameters ... whereas the first answer, above, gave youthe volume of the hole in the middle of everything. Here's my take on it:-- Volume of a sphere is 4/3 pi R3-- Volume enclosed by the outer radius is 4/3 pi (2)3-- Volume enclosed by the inner radius is 4/3 pi (1)3-- Volume of the material between them is4/3 pi (23 - 13) = 4/3 pi x 7 =28/3 pi = 29.32 m3. (rounded)The volume of a spherical shell is equal to the difference between the volume of a sphere with a radius of 2 m and a volume of a sphere with a radius of 1 meter:V= 29,321531433504736892318004910609 м3
x^2+y^2=36
No. The combined thickness of the inner and outer core is about 3500 to 3520 kilometers, out of the Earth's total radius of about 6370 kilometers. This means that the combination of inner solid core and liquid outer core has about 16% of the Earth's volume. *The reference to "1% of the Earth's volume" may refer to the Earth's crust, which has about "1% of the Earth's total mass."
It is not possible to find the volume from the two radii. That will only give the surface area of the disk that it forms. To find the volume yYou also need the thickness of .
You must use the relationship between the inner radius and the outer radius. The relationship could very well be different every time you run into a problem like this, and I can't answer the question this time because you haven't described any relationship between them.
Consider the volume of the pipe as the difference in the volume of two cylinders, one containing the whole pipe and the other the empty space inside. Use the formula for the volume of a cylinder : Pi*r*r*h. Find the volume of the first cylinder with the larger radius and subtract from it that of the cylinder with the smaller radius. The height (or length) is the same for both volume calculations. The result of subtracting these is the volume occupied by the pipe.
Outer or inner? The bone between the shoulder and the elbow is the humerus. The two bones in the forearm (between the elbow and the wrist) are the larger, longer bone, the radius, and the smaller bone, the ulna.