This can be found using one of the most important constants for chemistry: Avogadro's number.
According to wikipedia, the standard atomic weight of magnesium is 24.3050 grams per mole. Using Avogadro's number, we know there's 6.0221415 × 1023 atoms per mole, so if you divide the standard atomic weight of magnesium by Avogadro's number, you can get number of grams per atom of magnesium (i.e. the mass of a single magnesium atom in grams).
(24.3050 g/mole) / (6.0221415 x 1023 atoms/mole) = 4.03564 g/atom
In 8 mg Magnesium is:8(mg) / 24.31(mg/mmole) = 0.329 mmole Mg(molar mass Mg being 24.31 mg/mmole)In 0.329 mmole Mg is:0.329(mmole) * 6.02*1023(atoms/mole)*10-3(mole/mmole) == 1.98*1020 atoms of Mg.(Avogadro's Number being 6.02*1023)
The mass of the object would be 0.458 grams. This is calculated by dividing the mass in milligrams (458 mg) by the conversion factor (1000 mg per gram).
To calculate the number of magnesium (Mg) atoms in 2 grams of chlorophyll, we first need to determine the molar mass of chlorophyll, which is approximately 893.49 g/mol. Since chlorophyll contains 2.68% magnesium, the mass of magnesium in 2 grams of chlorophyll is 0.0536 grams. The number of moles of magnesium is calculated by dividing the mass by its atomic mass (24.31 g/mol), resulting in approximately 0.0022 moles. Finally, multiplying by Avogadro's number (6.022 x 10²³) gives about 1.32 x 10²¹ atoms of magnesium in 2 grams of chlorophyll.
1.346 grams Mg (1 mole Mg/24.31 grams) = 0.05537 moles magnesium
Magnesium has the molar mass of 24.305 grams per mole. 0.229 moles of Mg has a mass of about 5.57 grams.
1 mg = .001 grams, so .014 mg = 0.000014 grams
1 mole of any substance contains 6.022 x 10^(23) atoms/molecules. We have 1.5 x 10^(23) atoms Hence moles = 1.5 x 10^(23) / 6.022 x 10^(23) = 0.24908... moles(Mg) Also remember the eq'n moles = mass(g) / Ar Algebraically rearrange mass(g) = moles X Ar mass = 0.24908... X 24.3 (Ar of Mg ; from Periodic Table) Mass = 6.0528... g ~ 6 g
I assume you mean 40.59 grams of aluminum. 40.59 grams Al (1 mole Al/26.98 grams)(6.022 X 10^23/1 mole Al) = 9.05978 X 10^23 atoms in that mass aluminum 9.05978 X 10^23 atoms (1 mole Mg/6.022 X 10^23)(24.31 grams/1mole Mg) = 36.57 grams of magnesium
1 gram = 1000 mg
In 8 mg Magnesium is:8(mg) / 24.31(mg/mmole) = 0.329 mmole Mg(molar mass Mg being 24.31 mg/mmole)In 0.329 mmole Mg is:0.329(mmole) * 6.02*1023(atoms/mole)*10-3(mole/mmole) == 1.98*1020 atoms of Mg.(Avogadro's Number being 6.02*1023)
The mass of the object would be 0.458 grams. This is calculated by dividing the mass in milligrams (458 mg) by the conversion factor (1000 mg per gram).
Divide mg by 1,000 to get the same mass in grams. 1,000 mg = 1 gram 900 mg = 0.9 gram
Mg is mega grams (million grams = tonnes) mg is milligrams (thousandths of a gram)3000 Mg is 3000 tonnes or the mass of a small destroyer ship3000 mg is 3 grams or the mass of a coin (slightly more than a US penny)
0.3456 g
According to the US Mint, a quarter has a mass of 5.670 grams, so that is 5670 mg.
Grams is used to measure mass. It is equal to 1000 mg.
For this you need the atomic mass of Mg. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.4.637 grams Mg / (24.3 grams) = .191 moles Mg