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The mass number for molybdenum (Mo) varies depending on its isotopes. The most common isotope, molybdenum-98, has a mass number of 98. Other stable isotopes include Mo-92, Mo-94, Mo-95, Mo-96, and Mo-97, with mass numbers ranging from 92 to 97. Therefore, the mass number for Mo can differ based on the specific isotope being referenced.

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How many protons and neutrons does the element MO have?

Molybdenum-96 (not Mo-96) or Mo 96 42 has 42 protons and 54 neutrons. The atomic number is number of protons The mass number minus the atomic number is number of neutrons


What is Mo atomic mass?

The atomic mass of molybdenum (Mo) is approximately 95.94 amu (atomic mass units).


What is the mass number of molybdenum?

The atomic number of molybdenum (Mo) is 42. See the Web Links to the left of this answer for a periodic table with more information about this element!


Mo is thinking of a number. Eleven more than one third of the number is -1 find Mo's number?

The number is -36


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The history of mass commuication in the philippines is putangina mo gago.


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Mo Williams is number 25 on the Portland Trail Blazers.


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Stewie by mo


What is the oxidation number for MO?

The oxidation number for the compound MO can vary depending on M. In general, oxygen has an oxidation number of -2. Therefore, you would need to know what element M represents in order to determine the oxidation number for MO.


What does NE and mo mean in your CBC blood?

LY#. Lymphocyte number. MO#. Monocyte number. NE#. Neutrophil number


What element is the number of protons and neutrons in the nucleus?

All elements have neutrons and protons within the nucleus.


Mo is thinking of a number eleven more than one third of the number is -1 find mo's number?

The number is -36 because (1/3 of -36) + 11 = -1


What chemical has 53 neutrons and 42 electrons?

42 electrons implies atomic number of 42, which implies that it's molybdenum. With 42 electrons implies 42 protons implies an atomic mass of 42+53=95 which is 95Mo, one of the stable isotopes of this element. Please see the link.