1.6g
The molar mass of the substance is 15.2 g/mol (0.76 g divided by 0.05 mol). Therefore, the mass of 0.05 moles would be 0.76 g.
The answer is1.77 * 10-6 M.Solution:.7 ug * (1 g \ 106 ug) This converts our value from micrograms (ug) to grams (g).* (1 mole Selenium \ 78.96 g Selenium) This gives out our # of moles Selenium by using Selenium's molar mass (78.96 g/mol).= 8.87 * 10-9 moles SeleniumDivided by the volume in liters (.005 L)= 1.77 * 10-6 moles Selenium \ 1 L (M)Check:.005 L * (1.77 * 10-6 moles Selenium\ 1 L)= .00000177 moles Selenium* (78.96 g Selenium \ 1 mole Selenium)* (106 ug \ 1 g)~= .7 ug.- Mike
Some conversion required. (mmolar into mol, or moles into mmol ) Molarity = moles of solute/Liters of solution 100 millimolar = 0.1 M glycine Molarity = moles of solute/Liters of solution manipulate algebraically Liters of solution = moles of solute/Molarity 0.005 mole glycine/0.1 M glycine = 0.05 Liters ( 1000 ml/1 L) = 50 milliliters of solution --------------------------------
.005 teaspoon is equal to approximately 0.00010416667 ounces.
5 ppm means that there are 5 grams of solute in every 1 million grams of solution. Therefore, in a 1000-gram solution, the total mass of solute would be 0.005 grams.
The molar mass of the substance is 15.2 g/mol (0.76 g divided by 0.05 mol). Therefore, the mass of 0.05 moles would be 0.76 g.
005 is thicker than 003
.005= .5%
005 = 5
005 = 5 so the reciprocal of 005 = reciprocal of 5 = 1/5 = 0.2
3650 * 005 = 18,250
15
It is 005 percent!
x - 0.5% = 500x - .005 = 500x - .005 + .005 = 500 + .005x = 500.005Check:x = 500.005500.005 - 0.5% = 500500.005 - .005 = 500500 = 500So x - 0.5% = 500 when x is .005.
005% = 5% which, as a decimal is 0.05
.010 is thicker than .005
The answer is1.77 * 10-6 M.Solution:.7 ug * (1 g \ 106 ug) This converts our value from micrograms (ug) to grams (g).* (1 mole Selenium \ 78.96 g Selenium) This gives out our # of moles Selenium by using Selenium's molar mass (78.96 g/mol).= 8.87 * 10-9 moles SeleniumDivided by the volume in liters (.005 L)= 1.77 * 10-6 moles Selenium \ 1 L (M)Check:.005 L * (1.77 * 10-6 moles Selenium\ 1 L)= .00000177 moles Selenium* (78.96 g Selenium \ 1 mole Selenium)* (106 ug \ 1 g)~= .7 ug.- Mike