If 4 is cm3 and salt is NaCl the mass is 8,66 g.
The mass and the volume
To find the volume of the salt, we use the mass of kerosene displaced. Since 7.6 g of kerosene is displaced, the volume of the salt can be calculated using the density of kerosene: [ \text{Volume of salt} = \frac{\text{mass of kerosene}}{\text{density of kerosene}} = \frac{7.6 , \text{g}}{0.83 , \text{g/cm}^3} \approx 9.15 , \text{cm}^3. ] Next, we find the density of the salt using its mass and the calculated volume: [ \text{Density of salt} = \frac{\text{mass of salt}}{\text{volume of salt}} = \frac{20 , \text{g}}{9.15 , \text{cm}^3} \approx 2.19 , \text{g/cm}^3. ]
Density is a property of matter representing the mass per unit volume. :)
To find the volume of the rock, you can use the formula: Volume = Mass / Density. Plug in the values: Volume = 16 grams / 4 g/ml = 4 ml. So, the rock occupies a volume of 4 ml.
For a volume of approx. 5 mL the mass is approx. 7 g.
Density = Mass/Volume As salt(mass) increases and the volume remains the same, density also increases.
The mass and the volume
Dissolving salt in water does not change the total mass of the salt and water. The mass of the combined system will be the sum of the mass of the salt and the mass of the water. However, the volume of the solution will increase due to the added salt.
To find the volume of the salt, we use the mass of kerosene displaced. Since 7.6 g of kerosene is displaced, the volume of the salt can be calculated using the density of kerosene: [ \text{Volume of salt} = \frac{\text{mass of kerosene}}{\text{density of kerosene}} = \frac{7.6 , \text{g}}{0.83 , \text{g/cm}^3} \approx 9.15 , \text{cm}^3. ] Next, we find the density of the salt using its mass and the calculated volume: [ \text{Density of salt} = \frac{\text{mass of salt}}{\text{volume of salt}} = \frac{20 , \text{g}}{9.15 , \text{cm}^3} \approx 2.19 , \text{g/cm}^3. ]
The most correct term for solid sodium chloride quantity is mass of salt.
Yes, always for all mixtures.Interestingly, the volume of the solution may not equal the volume of the two things before being mixed -- even for mixing two liquids.
There is not much to calculate here - 4 cm3 is the volume. The mass is irrelevant for this problem.There is not much to calculate here - 4 cm3 is the volume. The mass is irrelevant for this problem.There is not much to calculate here - 4 cm3 is the volume. The mass is irrelevant for this problem.There is not much to calculate here - 4 cm3 is the volume. The mass is irrelevant for this problem.
you need the mass and radius of the sphere- density = mass divided by volume, so mass/volume. the volume of a sphere is 4 divided by 3 multiplied by pi multiplied by the radius squared. 4/3(π)(r^2).
Gram is a unit of mass and milliliter is a unit of volume.
This well known formula should lead you on your path: Density (grams/ml) = mass/volume
Density is the mass per unit volume. Therefore, adding salt increases the mass of the water by a larger scale than it does the volume of the water. Actually when you add salt to the same volume of water the mas of the water has a noticeable increase, where as the volume appears to the same ( the volume does increase; however the change is so small that it is unnoticeable ,thus we say it stays the same). So a larger mass divided by the same volume gives you an increase in density.
Yes, it will eventually. When you add salt to water, you are increasing the density of the solution, but not the volume, because the salt dissolves (dissociates). Since density is mass divided by volume, there is a direct relationship between the solution's mass and its density. They increase together even as the volume remains constant. An egg will float in a salt solultion if the molarity is about 2.5 or above.