For a given perimeter, the greatest possible area is enclosed by a circle.A circle with a circumference of 18 has a diameter of (18/pi) and a radius of (9/pi).Its area is (pi R2) = (pi 92/pi2) = 81/pi = 25.78 (rounded)So an area of 42 cannot be enclosed by a perimeter of 18.
Spring tides have a greater tidal range than neap tides.
The amplitude of a transverse wave represents the maximum displacement of a particle from its equilibrium position. It is typically measured in centimeters (cm) and signifies the maximum distance the wave can move up or down from its resting point.
It is a fuse, a piece of metal wire, usually in a glass tube, that can only just carry the maximum allowed current. A current greater than the maximum allowed will melt the wire.
Tin (Sn) has the most number of isotopes with over 30 known isotopes. This is because it has a large atomic number and therefore a greater range of possible isotopes.
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
As stated the question is impossible since such a rectangle cannot exist. The area of a rectangle is measured in square units of length not in centimetres. Assuming the area is 49 square centimetres, the perimeter can be any number greater than 28 cm. Consider a rectangle of length L cm where L is any number greater than 7. Let W = 49/L cm be the width of the rectangle. Then the area of the rectangle is L*W = L*49/L = 49 cm. The perimeter can be increased by making the rectangle longer and thinner. And this can be done without any maximum limit. L can be 100 cm, 1 kilometre, 1 million kilometres, anything! Try it and see - and the perimeter is 2*(L+W)
100 cm2
1024
A square of side 22 has an area of 484. Rectangle 23 x 21 has an area of 483...
130/4 (4 sides to a rectangle)= 32.5 32.5*32.5=1065.25 square meters (because the largest area of a rectangle is always a ^ ^ square). length width
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
The maximum area with straight sides and a given perimeter is a square.The sides of the square are (68/4) = 17 inches.The area is (17 x 17) = 289 square inches
The rectangle with the most area for a given perimeter is the square.Build the room square, with sides of 94-ft. The area is 8,836 square ft.
81 sq cm, for a 9 cm * 9 cm square
By using Differential Calculus. Any rectangle is at a maximum area when it is a square. So taking 108 and dividing by '4' We have '27' This is the length of one side of the square So its areis A(sq) = 27^2 = 729 m^2
Perimeter is a unit of length. Area is a unit of area. The two units are not directly convertible.However, the area of a rectangle is length times width, and the perimeter is two times length plus two times width. Given constant perimeter, a square has maximum area, while a very thin rectangle has nearly zero area. (In calculus terms, the limit of the area as length or width goes to zero is zero.)Depending on how you want to name your units, you can always find a rectangle whose perimeter is "larger" than area, but this is a numerical trick that is not valid in any school of thought of mathematics that I know.