The maximum length is 25 cm.
To find the dimensions of a rectangle with a perimeter of 200 feet, we can use the formulas for perimeter (P = 2(l + w)) and area (A = l * w). Given that the perimeter is 200 feet, we have ( l + w = 100 ). However, for the area to be less than 100 square feet, the dimensions must be such that ( l * w < 100 ). Since the maximum area occurs when ( l ) and ( w ) are equal, the dimensions would need to be less than 10 feet each, which is not possible under these constraints. Therefore, no rectangle can satisfy both conditions.
For a given perimeter, the greatest possible area is enclosed by a circle.A circle with a circumference of 18 has a diameter of (18/pi) and a radius of (9/pi).Its area is (pi R2) = (pi 92/pi2) = 81/pi = 25.78 (rounded)So an area of 42 cannot be enclosed by a perimeter of 18.
A local maximum in a table refers to a value that is greater than its immediate neighbors in the dataset. In a two-dimensional table, this means a value is a local maximum if it is greater than the values directly adjacent to it—vertically and horizontally. Local maxima can indicate points of interest or peaks in the data, but they do not necessarily represent the highest value in the entire dataset.
Spring tides have a greater tidal range than neap tides.
The amplitude of a transverse wave represents the maximum displacement of a particle from its equilibrium position. It is typically measured in centimeters (cm) and signifies the maximum distance the wave can move up or down from its resting point.
As stated the question is impossible since such a rectangle cannot exist. The area of a rectangle is measured in square units of length not in centimetres. Assuming the area is 49 square centimetres, the perimeter can be any number greater than 28 cm. Consider a rectangle of length L cm where L is any number greater than 7. Let W = 49/L cm be the width of the rectangle. Then the area of the rectangle is L*W = L*49/L = 49 cm. The perimeter can be increased by making the rectangle longer and thinner. And this can be done without any maximum limit. L can be 100 cm, 1 kilometre, 1 million kilometres, anything! Try it and see - and the perimeter is 2*(L+W)
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
100 cm2
1024
A square of side 22 has an area of 484. Rectangle 23 x 21 has an area of 483...
130/4 (4 sides to a rectangle)= 32.5 32.5*32.5=1065.25 square meters (because the largest area of a rectangle is always a ^ ^ square). length width
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
The maximum area with straight sides and a given perimeter is a square.The sides of the square are (68/4) = 17 inches.The area is (17 x 17) = 289 square inches
If the perimeter of a rectangle is 16 inches, the formula for the perimeter is ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. Setting the perimeter equal to 16 gives us ( l + w = 8 ). The area ( A ) of the rectangle is calculated as ( A = l \times w ). Without specific dimensions for length and width, the area can vary; however, the maximum area occurs when the rectangle is a square with each side measuring 4 inches, giving an area of ( 16 ) square inches.
The rectangle with the most area for a given perimeter is the square.Build the room square, with sides of 94-ft. The area is 8,836 square ft.
To find the area of a rectangle with a perimeter of 24 units, we can use the formula for perimeter: ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. This gives us ( l + w = 12 ). The area ( A ) is calculated using ( A = l \times w ). The maximum area occurs when the rectangle is a square, leading to dimensions of 6 units by 6 units, resulting in an area of 36 square units.
By using Differential Calculus. Any rectangle is at a maximum area when it is a square. So taking 108 and dividing by '4' We have '27' This is the length of one side of the square So its areis A(sq) = 27^2 = 729 m^2