The min and max temp of mars i 1,299 degrees celcius and -1,000,000 degrees celcius
#include<iostream.h> void main() { double sum=0,avg,max=0,min=100,temp[12]; char *Month[]={"Jan", "Feb", "Mar", "Apr", "May", "Jun","Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; for(int j=0;j<12;j++){ cout << "Enter the temperature of month :"<<*(Month+j)<< endl; cin >> temp[j]; sum=sum+temp[j]; } avg=sum/12; for(int i=0;i<12;i++){ if(temp[i]>max) max=temp[i]; if(temp[i]<min) min=temp[i];} cout << "Average temperature of the year: " << avg << endl; cout << "Maximum temperature of the year: " << max << endl; cout << "Minimum temperature of the year: " <<min << endl; }
Mars tempature is much greater than earth
Usually, max 212 F and min 32 F It depends on for what the thermometer will be used. My greenhouse min/max thermometer has a min of -40°F and a max of 120°F A (non-digital) clinical thermometer has a min of 94°F and a max of 108°F A cook's (sugar/jam) thermometer has a min of 100°F and a max of 400°F
You can use the SEQUENCE function in Excel to create a series of numbers from max to min or min to max. For example, to create a series from 10 to 1 in descending order, you could use =SEQUENCE(10,1,-1). This formula generates a range of numbers from 10 to 1 in descending order.
The reason we use max for union is because the union of two sets should include all elements from both sets, so the max operation ensures that the larger of the two elements is included. Conversely, we use min for intersection because we want to find the common elements shared by both sets, so the min operation ensures we only include elements that are in both sets.
#include<stdio.h> #include<conio.h> void main(void) { int max=0,min=0; int temp; int n,i; clrscr(); printf("what is the lenght of number set?\n"); scanf("%d",&n); printf("\n\nNow enter the numbers\n"); for(i=1;i<=n;i++) { scanf("%d",&temp); if(temp>max)max=temp; if(i==1)min=temp; if(temp<min)min=temp; } printf("\n\nThe range of set is %d",max-min); getch(); }
No, it lowers both the max and min temperature.
198 degrees min running temp. 210 max running temp. The hotter the temp the more fuel economy.
Min −87 °C Mean −46 °C Max −5 °C
#include<iostream.h> void main() { double sum=0,avg,max=0,min=100,temp[12]; char *Month[]={"Jan", "Feb", "Mar", "Apr", "May", "Jun","Jul", "Aug", "Sep", "Oct", "Nov", "Dec"}; for(int j=0;j<12;j++){ cout << "Enter the temperature of month :"<<*(Month+j)<< endl; cin >> temp[j]; sum=sum+temp[j]; } avg=sum/12; for(int i=0;i<12;i++){ if(temp[i]>max) max=temp[i]; if(temp[i]<min) min=temp[i];} cout << "Average temperature of the year: " << avg << endl; cout << "Maximum temperature of the year: " << max << endl; cout << "Minimum temperature of the year: " <<min << endl; }
fro implementing selection sort yiou have to first find the max or the min value in the array; here you go: for(i=0;i<=maxsize;i++) { min=a[i]; loc=i; for(j=1;j<=maxsize;j++) { if(min>a[j]) { min=a[j]; loc=j; } } if(loc!=i) { temp=a[i]; a[i]=a[loc]; a[loc]=temp; } }
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Max Temp went out of business
Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. Steps to perform MaxMin on a data set (2,4,6,3,8,1,9,7) are:(2,4,6,3) (8,1,9,7)((2,4)(6,3)) ((8,1)(9,7))In sublist (4,6), max is 6 and min is 4. In sublist (8,9), max is 9 and min is 8.Comparing max and min values of sublist (2,4) and sublist (6,3), value of max is 6 and min is 2.Therefore, for sublist (2,4,6,3) max is 6 and min is 2.Similarly, comparing max and min values of sublist (8,1) and sublist (9,7), value of max is 9 and min is 1.Therefore, for sublist (8,1,9,7) max is 9 and min is 1.Finally, comparing max and min values of sublist (2,4,6,3) and sublist (8,1,9,7), value of max is 9 and min is 1. sonika aggarwal GNIIT
Mars tempature is much greater than earth
The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)The MIN function returns the lowest value from a set of values. The MAX function returns the highest value from a set of values.=MIN(A2:A20)=MAX(A2:A20)
int sum (int min, int max) {return (max-min+1)*(max+min)/2;}