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To find the molarity (M) of the solution, first calculate the number of moles of KI. The molar mass of KI is approximately 166 g/mol (39 g/mol for K and 127 g/mol for I). So, the number of moles in 36.52 g of KI is 36.52 g ÷ 166 g/mol ≈ 0.22 moles. The volume of the solution in liters is 820 ml ÷ 1000 = 0.82 L. Therefore, the molarity is M = moles/volume = 0.22 moles / 0.82 L ≈ 0.27 M.
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What is the molarity of 820mL of Kl solution that contains 36.52g of Kl?
To find the molarity (M) of the KI solution, first convert grams of KI to moles using its molar mass (KI's molar mass is approximately 166 g/mol). Moles of KI = 36.52 g / 166 g/mol ≈ 0.220 moles. Then, convert the volume from mL to liters: 820 mL = 0.820 L. Finally, calculate the molarity: M = moles/volume = 0.220 moles / 0.820 L ≈ 0.268 M. Thus, the molarity of the KI solution is approximately 0.268 M.
What is the molarity of 820 mL of KI solution that contains 36.52 g of KI?
To find the molarity, first calculate the number of moles of KI using its molar mass (KI has a molar mass of approximately 166 g/mol). The number of moles is calculated as follows: [ \text{Moles of KI} = \frac{36.52 \text{ g}}{166 \text{ g/mol}} \approx 0.22 \text{ moles} ] Next, convert the volume from mL to liters: ( 820 \text{ mL} = 0.820 \text{ L} ). Finally, calculate the molarity (M): [ \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} = \frac{0.22 \text{ moles}}{0.820 \text{ L}} \approx 0.27 \text{ M} ] Thus, the molarity of the KI solution is approximately 0.27 M.
What is the molarity of 820 mL of potassium iodide solution that contains 36.52 g of potassium iodide?
To calculate the molarity (M) of the potassium iodide (KI) solution, first determine the number of moles of KI. The molar mass of KI is approximately 166 g/mol, so: [ \text{Moles of KI} = \frac{36.52 , \text{g}}{166 , \text{g/mol}} \approx 0.219 , \text{mol} ] Next, convert the volume from mL to liters: [ 820 , \text{mL} = 0.820 , \text{L} ] Now, calculate the molarity: [ M = \frac{0.219 , \text{mol}}{0.820 , \text{L}} \approx 0.267 , \text{M} ] Thus, the molarity of the potassium iodide solution is approximately 0.267 M.
What is the molarity of 820 mL Kl solution that contains 36.52g of Kl?
To find the molarity (M) of the KCl solution, first calculate the number of moles of KCl using the formula: moles = mass (g) / molar mass (g/mol). The molar mass of KCl is approximately 74.55 g/mol. Thus, moles of KCl = 36.52 g / 74.55 g/mol ≈ 0.489 moles. Finally, convert the volume from mL to L (820 mL = 0.820 L) and use the molarity formula: M = moles/volume(L), which gives M ≈ 0.489 moles / 0.820 L ≈ 0.597 M.
Convert 820 miles to kilometers?
820 miles is equal to 1,319.7 kilometersAlgebraic Steps / Dimensional Analysis Formula 820 mi*63360 in1 mi*2.54 cm1 in*1 km100000 cm=1,319.66208 kmDirect Conversion Formula 820 mi*1.609344 km1 mi=1,319.66208 km
What is the molarity of 820mL of Kl solution that contains 36.52g of Kl?
To find the molarity (M) of the KI solution, first convert grams of KI to moles using its molar mass (KI's molar mass is approximately 166 g/mol). Moles of KI = 36.52 g / 166 g/mol ≈ 0.220 moles. Then, convert the volume from mL to liters: 820 mL = 0.820 L. Finally, calculate the molarity: M = moles/volume = 0.220 moles / 0.820 L ≈ 0.268 M. Thus, the molarity of the KI solution is approximately 0.268 M.
What is the molarity of 820 mL of KI solution that contains 36.52 g of KI?
To find the molarity, first calculate the number of moles of KI using its molar mass (KI has a molar mass of approximately 166 g/mol). The number of moles is calculated as follows: [ \text{Moles of KI} = \frac{36.52 \text{ g}}{166 \text{ g/mol}} \approx 0.22 \text{ moles} ] Next, convert the volume from mL to liters: ( 820 \text{ mL} = 0.820 \text{ L} ). Finally, calculate the molarity (M): [ \text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}} = \frac{0.22 \text{ moles}}{0.820 \text{ L}} \approx 0.27 \text{ M} ] Thus, the molarity of the KI solution is approximately 0.27 M.
What is equivalent to 20 41s?
820
What is 822 rounded to the nearest 10?
820
How many grams of copper(II) fluoride are needed to make 6.7 L of a 1.2 M solution?
It requires 8.0 grams of copper (II) fluoride to make 6.7 liters of a 1.2 M solution. The equations required to come to this conclusion as well as the rest of the answer key for this assignment can be found on the Molarity Practice Problems website. Revised Version: That is completely wrong! The answer is 820 grams. My chem teacher corrected it.
What is 25 percent of 820?
25% of 820= 25% * 820= 0.25 * 820= 205
What is 2 percent of 820?
2% of 820 = 2% * 820 = 0.02 * 820 = 16.4
What is 32 percent of 820?
32% of 820 = 32% * 820 = 0.32 * 820 = 262.4
822 to nest ten?
820
What are the first ten multiples of 820?
The first ten positive integer multiples of 820 are: 1 x 820 = 820 2 x 820 = 1640 3 x 820 = 2460 4 x 820 = 3280 5 x 820 = 4100 6 x 820 = 4920 7 x 820 = 5740 8 x 820 = 6560 9 x 820 = 7380 10 x 820 = 8200
how much is 82 tens?
82 tens =82 × 10 = 820
What is the mg of an Watson 820 pill?
A Watson 820 pill is a yellow, round pill. It's a generic form of Percodan which contains Oxycodone and Asprin, pretty much just like Percocet. The pill contains Oxycodone HCL 4.5mg/ Oxycodone Terephthalate 0.38 mg, and 325mg of Asprin.
