These two compounds doesn't react.
Barium chloride and sodium sulfate Molecular equation: BaCl2(aq) + Na2SO4(aq)--> BaSO4(s) + 2NaCl(aq) ionic equation: Ba+2(aq) + 2Cl-(aq) + 2Na+(aq) + SO4-2(aq) --> BaSO4(s) + 2Na+(aq) + 2Cl-(aq) Net ionic equation is Ba+2(aq) + SO4-2(aq) --> BaSO4(s)
Molecular
PtO2 is ionic
For the molecular balance of the equation it would be: CuSO4 (aq) + Na2S (aq) = CuS (s) + Na2SO4 (aq). For the net ionic balance of the equation it would be: Cu2+ (aq) + S2(aq) = CuS (s).
CO is a molecular compound. It consists of a covalent bond between carbon and oxygen atoms.
chromium disodium phosphate
Molecular equation: CuSO4 + Na2CO3 → CuCO3 + Na2SO4 Net ionic equation: Cu2+ + CO3^2- → CuCO3
A molecular equation shows all reactants and products as full compounds without distinguishing between ionic and covalent bonds, while a complete ionic equation breaks down all ionic compounds into their individual ions in a solution. It explicitly shows the ions present and their charges in a chemical reaction.
In a molecular equation, all reactants and products are written as complete formulas, while in an ionic equation, only ions that participate in the reaction are written. Ionic equations focus on the dissociation of ionic compounds into their constituent ions, whereas molecular equations do not show this dissociation. Ionic equations provide a more accurate representation of the species involved in a reaction in solution compared to molecular equations.
A chemical equation can be interpreted in terms of molecular, ionic, or net ionic equations. In a molecular equation, all reactants and products are written as complete compounds. In an ionic equation, all soluble compounds are dissociated into their respective ions. In a net ionic equation, spectator ions are omitted to show only the species that participate in the chemical reaction.
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
To write a complete ionic equation for a chemical reaction, first write the balanced molecular equation. Then, break down all the ionic compounds into their respective ions. Include only the ions that are involved in the reaction. Finally, write the complete ionic equation by showing all the ions present before and after the reaction.
The balanced complete ionic equation for Na2CO3 (sodium carbonate) and copper nitrate would be: 2Na+(aq) + CO3^2-(aq) + 2Cu2+(aq) + 4NO3-(aq) -> 2Na+(aq) + 2NO3-(aq) + 2CuCO3(s) This equation shows all ions present in the reaction before and after the reaction takes place.
Balanced equation: Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa Net ionic equation: Cu^2+ + CO3^2- -> CuCO3
To write a complete ionic equation, first write the balanced molecular equation. Then, break down all strong electrolytes into their respective ions. Include only the ions that participate in the reaction, and balance the charges on both sides of the equation.
nickel sulfate + sodium carbonate -> sodium sulfate + nickel carbonate
the spectator ions are removed