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What is the the orbital distance traveled in 1 2 and 3 seconds for Venus Mars and Jupiter?
To calculate the orbital distance traveled by Venus, Mars, and Jupiter in 1, 2, and 3 seconds, we can use their average orbital speeds. Venus travels at about 35 km/s, Mars at approximately 24 km/s, and Jupiter at roughly 13 km/s. Therefore, in 1 second, Venus travels about 35 km, Mars about 24 km, and Jupiter about 13 km. In 2 seconds, the distances would be 70 km for Venus, 48 km for Mars, and 26 km for Jupiter, while in 3 seconds, they would be 105 km, 72 km, and 39 km, respectively.
How many seconds slower is Jupiter from Saturn orbital speed?
Jupiter orbits the Sun at an average speed of about 13.07 kilometers per second, while Saturn orbits at approximately 9.69 kilometers per second. This means that Jupiter is about 3.38 kilometers per second faster than Saturn. To convert this difference into seconds, you would calculate the time it takes for each planet to complete an orbit, but generally, Jupiter is not slower; it is actually faster in its orbital speed compared to Saturn.
Distance traveled in feet after 12 seconds and 87 miles per hour?
After 12 seconds, a car traveling at 87 miles per hour would have traveled approximately 1,520 feet. This can be calculated by first converting 87 miles per hour to feet per second, which is about 128 feet per second. Multiplying this by the number of seconds gives the distance traveled.
How do you compute Jupiter's orbital period around the sun in earth's days?
You first need two things: a) the mass of the Sun and b) Jupiter's orbital distance from the Sun. You can easily look up these values in any astronomy book. Once you got both down, apply the formula (which comes from Kepler's Third Law of Planetary Motion)R3 = GMT2 / 4Pi2whereR = the orbital distance of the planet (in meters)G = the Gravitational Constant (whose value is 6.673x10-11)M = the mass of the Sun (1.98x1030 kg)T = the orbital period of the planet (in seconds). This is your target value.The other operands are straightforward.At this point, all you need to do is substitute the appropriate values in the formula, then rearrange and solve for T. Make absolutely certain you take into account the units; in this case, T will be calculated in seconds. When you have the value of T in seconds at the end of your calculation, simply convert it to days and you will get your answer. (Hint: There are 86,400 seconds in a standard Earth-day.)
How do i convert 2.97 seconds into feet?
This is impossible. Seconds are a measure of time and feet are a measurement of length.
What is the the orbital distance traveled in 1 2 and 3 seconds for Venus Mars and Jupiter?
To calculate the orbital distance traveled by Venus, Mars, and Jupiter in 1, 2, and 3 seconds, we can use their average orbital speeds. Venus travels at about 35 km/s, Mars at approximately 24 km/s, and Jupiter at roughly 13 km/s. Therefore, in 1 second, Venus travels about 35 km, Mars about 24 km, and Jupiter about 13 km. In 2 seconds, the distances would be 70 km for Venus, 48 km for Mars, and 26 km for Jupiter, while in 3 seconds, they would be 105 km, 72 km, and 39 km, respectively.
What is the distance that the object travels in the first 5 seconds?
To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.
How do you Determine the speed of an object that traveled 50 meters in 2 seconds?
Speed = (distance traveled) divided by (time to cover the distance) Speed = (50 meters) / (2 seconds) Speed = 50 meters per 2 seconds Speed = 25 meters per second
If you traveled 50 meters in 25 seconds what is your distance traveled and average speed?
2 meters every second. bit pointless
How long does it take reflected light from Jupiter to reach the earth?
Jupiter and Earth are not always the same distance apart. At their closest, it would take about 1.96 seconds. At their furthest, about 3.22 seconds.
How many seconds slower is Jupiter from Saturn orbital speed?
Jupiter orbits the Sun at an average speed of about 13.07 kilometers per second, while Saturn orbits at approximately 9.69 kilometers per second. This means that Jupiter is about 3.38 kilometers per second faster than Saturn. To convert this difference into seconds, you would calculate the time it takes for each planet to complete an orbit, but generally, Jupiter is not slower; it is actually faster in its orbital speed compared to Saturn.
What is the rate at which you cover a certain distance?
The rate that you cover a distance is your speed. Speed is a measure of the distance traveled per unit time. If your units are meters and seconds, then your speed would be in meters/second. To find the speed of something you divide the distance it traveled by the time it took to travel that distance. For example if something traveled 40 meters in 10 seconds its speed would be (40 meters)/(10 seconds) = 4 meters/second
What is the average speed from 4s to 8s?
To find the average speed from 4 seconds to 8 seconds, you need the total distance traveled during that time interval and the total time taken. The average speed is calculated by dividing the total distance by the total time (4 seconds in this case). If you provide the distance traveled during that period, I can help you calculate the average speed.
Distance traveled in feet after 12 seconds and 87 miles per hour?
After 12 seconds, a car traveling at 87 miles per hour would have traveled approximately 1,520 feet. This can be calculated by first converting 87 miles per hour to feet per second, which is about 128 feet per second. Multiplying this by the number of seconds gives the distance traveled.
An automobile traveling at a velocity of 16 meters per second is brought to a full stop in 8 seconds The distance traveled in the 8 seconds is?
Speed= Distance / time => Distance = Speed x Time =16x8 = 128m
How do you compute Jupiter's orbital period around the sun in earth's days?
You first need two things: a) the mass of the Sun and b) Jupiter's orbital distance from the Sun. You can easily look up these values in any astronomy book. Once you got both down, apply the formula (which comes from Kepler's Third Law of Planetary Motion)R3 = GMT2 / 4Pi2whereR = the orbital distance of the planet (in meters)G = the Gravitational Constant (whose value is 6.673x10-11)M = the mass of the Sun (1.98x1030 kg)T = the orbital period of the planet (in seconds). This is your target value.The other operands are straightforward.At this point, all you need to do is substitute the appropriate values in the formula, then rearrange and solve for T. Make absolutely certain you take into account the units; in this case, T will be calculated in seconds. When you have the value of T in seconds at the end of your calculation, simply convert it to days and you will get your answer. (Hint: There are 86,400 seconds in a standard Earth-day.)
What is the speed of a bobsled whose distance-time graph indicates that it traveled 100 meters in 25 seconds?
To calculate the speed of the bobsled, you can use the formula for speed, which is distance divided by time. In this case, the bobsled traveled 100 meters in 25 seconds. Therefore, the speed is 100 meters ÷ 25 seconds = 4 meters per second.
