The oxidation of any element, by itself, is zero.
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
Chromium (Cr) has the hardest oxidation state among the listed metals. It commonly exhibits an oxidation state of +6 in compounds due to its high electronegativity and tendency to lose electrons.
Yes, it is. It shows two oxidation states: Cu(I) and Cu(II).
The product of Cu + Cl2 reacting to form CuCl2 is copper(II) chloride. In this reaction, the copper (Cu) reacts with chlorine (Cl2) to form copper(II) chloride (CuCl2) as the product.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
To find the oxidation number of copper (Cu) in CuO, consider that oxygen (O) usually has an oxidation number of -2. Since CuO is a neutral compound, the oxidation number of Cu can be calculated by setting up an equation where the sum of the oxidation numbers equals zero. In this case, the oxidation number of Cu in CuO is +2.
The oxidation number of Cu in Cu2S (copper sulfide) is +1. This is because the overall charge of the compound is 0 and there are two Cu atoms each with an oxidation state of +1.
The oxidation number of Cu in CuHSO4 is +1. This is because the overall charge of the compound is 0, and the oxidation number of H is +1, S is +6, and O is -2. By calculating the total oxidation numbers and assigning x to Cu, you can solve for x to find that Cu is in the +1 oxidation state.
Oxidation number is the charge per atom in a compound. Cl2= 2- (Cl= 1-) Cu would have to be 2+ to balance the compound, because there is only one copper atom.
The oxidation number tells you the "combining power" of that element. For example, if Cu has a 1+ oxidation number then it will combine with Cl in a 1:1 ratio, and result in CuCl. If Cu has an oxidation number of 2+, then it will combine with Cl in a 1:2 ratio, and result in CuCl2.
If the question is Cu2, then it is equivalent to Cu and the oxidation number for any element is zero. If the question is Cu2+, then the oxidation number is +2.
Oxidation number is the charge per atom in a compound. Cl2= 2- (Cl= 1-) Cu would have to be 2+ to balance the compound, because there is only one copper atom.
The oxidation number of copper (Cu) in CuF2 is +2. The oxidation number of fluorine (F) in compounds is almost always -1, and since there are two fluorine atoms in CuF2, the total negative charge is -2, which balances with the +2 oxidation state of copper.
The oxidation number of each copper (Cu) atom in CuCO3 is +2. The oxidation number of the oxygen (O) atoms in the carbonate ion (CO3) is -2, and the overall charge of the carbonate ion is -2.
In CuSO4, the oxidation number of copper (Cu) is +2, and the oxidation number of sulfur (S) is +6. This is because the overall charge of the sulfate ion (SO4) is -2.
The oxidation number of copper (Cu) in CuCO3 is +2. Oxygen typically has an oxidation number of -2, and the overall charge of the carbonate ion (CO3) is -2. Therefore, the oxidation number of copper is determined to be +2 in this compound.
In copper sulfate (CuSO4), the oxidation number of sulfur is +6. This is because the oxidation number of copper (Cu) is +2 and oxygen (O) typically has an oxidation number of -2, so the algebraic sum in the compound should be zero.