To find the total pressure inside the container, you can use Dalton's Law of Partial Pressures, which states that the total pressure is the sum of the partial pressures of the individual gases. Therefore, the total pressure would be 2.0 ATM (Ne) + 1.5 ATM (He) + 2.5 ATM (N2) = 6.0 ATM. Thus, the pressure inside the container is 6.0 ATM.
The total pressure inside the tank is the sum of the partial pressures of the gases present. In this case, Total pressure = partial pressure of oxygen + partial pressure of helium = 10 atm + 32.8 atm = 42.8 atm.
The pressure of the helium will decrease when placed in the larger container, following Boyle's Law. Using the formula P1V1 = P2V2, we can calculate the new pressure. So, (0.988 ATM)(1.00 L) = P2(4.40 L), which gives P2 = 0.225 ATM.
The initial total pressure is 1.0 ATM + 2.0 ATM = 3.0 ATM. Therefore, 6.0 ATM - 3.0 ATM = 3.0 ATM of helium was added to the tank. Hence, the partial pressure of helium in the tank is 3.0 ATM.
To find the pressure of gas B, you can use Dalton's Law of Partial Pressures, which states that the total pressure is the sum of the partial pressures of individual gases. Given that the total pressure is 1.20 ATM and the partial pressure of gas A is 0.75 ATM, you can calculate the pressure of gas B as follows: Pressure of gas B = Total pressure - Pressure of gas A = 1.20 ATM - 0.75 ATM = 0.45 ATM. Thus, the pressure of gas B is 0.45 ATM.
impossible to calculate
42.8 atm fufurjthfhhudjd
The total pressure inside the tank is the sum of the partial pressures of the gases present. In this case, Total pressure = partial pressure of oxygen + partial pressure of helium = 10 atm + 32.8 atm = 42.8 atm.
The pressure of the helium will decrease when placed in the larger container, following Boyle's Law. Using the formula P1V1 = P2V2, we can calculate the new pressure. So, (0.988 ATM)(1.00 L) = P2(4.40 L), which gives P2 = 0.225 ATM.
The initial total pressure is 1.0 ATM + 2.0 ATM = 3.0 ATM. Therefore, 6.0 ATM - 3.0 ATM = 3.0 ATM of helium was added to the tank. Hence, the partial pressure of helium in the tank is 3.0 ATM.
To find the pressure of gas B, you can use Dalton's Law of Partial Pressures, which states that the total pressure is the sum of the partial pressures of individual gases. Given that the total pressure is 1.20 ATM and the partial pressure of gas A is 0.75 ATM, you can calculate the pressure of gas B as follows: Pressure of gas B = Total pressure - Pressure of gas A = 1.20 ATM - 0.75 ATM = 0.45 ATM. Thus, the pressure of gas B is 0.45 ATM.
To find the new pressure, we can use the combined gas law which states P1/T1 = P2/T2. Plugging in the values: P1 = 2.10 ATM, T1 = 21°C + 273 = 294 K, T2 = 99°C + 273 = 372 K, we can solve for P2. The new pressure would be approximately 2.80 ATM.
The pressure of gas B can be calculated by subtracting the partial pressure of gas A from the total pressure. Therefore, the pressure of gas B would be 1.20 atm - 0.75 atm = 0.45 atm.
ATM card readers built inside the ATM machines can read the magnetic strip that contains every information about the ATM card including the PIN number.
impossible to calculate
0.125 moles
The answer is 0,125 moles.
To find the partial pressure of O₂, we need to calculate its mole fraction in the mixture. The total moles in the container is 3 + 2 + 1 = 6 moles. The mole fraction of O₂ is 2/6 = 1/3. As the total pressure is 8.7 atm, the partial pressure of O₂ is the mole fraction of O₂ multiplied by the total pressure, giving 1/3 * 8.7 = 2.9 atm.