About 50%, if there are no other genes available.
In this case, it doesn't matter what the genotype of the other parent is since BB is homozygous dominant (assuming this is the only gene that affects coat colour of course). All of the BB parent's offspring will PHENOTYPICALLY be brown-coated. They may be heterozygous though (Bb) depending on genotype of the second parent. So the PHENOTYPIC probability of a brown coat is 100% The genotypic probability of a homozygous genotype depends on the second parent.
a brown horse i just did this in school a few weeks ago
The phenotype is the physical/observable trait of the animal - therefore the phenotype of this rabbit is black fur.The genotype, Bb, makes this rabbit heterozygous.
Yes, buy only if the parents are heterozygous for the trait and if the trait is dominant.
Genetically speaking, there are roughly 8 well known 'Brown' mice. They all have different genes, which creates different shades. You should probably find out what shade of brown this 'Brown' mouse in question is. There is only one type of Black genetic colouring in mice. Generally speaking, if we were just using the common Agouti brown mouse (wild colour) & crossed it to Black, then the entire litter should've resulted in Agouti mice. However, Agouti being represented by a dominant A-, & the Black being represented by a recessive AA, crossing A- to AA would result in an entire litter of Aa = Agouti carring Black. If you crossed one of those offspring back to the Black parent, you would get Aa & AA in the litter, resulting in the litter being 50% black, 50% Agouti. However, if the 'Brown' mouse wasn't Agouti, & was actually another brown called Chocolate (I'm serious), then crossing Black (which in this case will be BB) to Chocolate (bb) would result in an entire litter of Blacks carrying Chocolate (Bb) . If you crossed 2 of the offspring together, you would get a mix of Blacks & Chocolates. NB: Black is a dominant gene to all other genes but Agouti.
In this case, it doesn't matter what the genotype of the other parent is since BB is homozygous dominant (assuming this is the only gene that affects coat colour of course). All of the BB parent's offspring will PHENOTYPICALLY be brown-coated. They may be heterozygous though (Bb) depending on genotype of the second parent. So the PHENOTYPIC probability of a brown coat is 100% The genotypic probability of a homozygous genotype depends on the second parent.
Black coat homozygous: BB Black Coat heterozgous: Bb
If the stallion carries the a gene and is heterozygous for roan your chances of a true blue roan are 50% if your mare is Ee. If she is EE there is no chance of a chestnut coated foal so the color of the foal will be controlled by the genetics of the stallion at the agouti site...either brown, bay or black.
If both parents are heterozygous for brown eyes (Bb), the possible allele combinations for their children can be represented in a Punnett square: BB, Bb, Bb, and bb. This means there is a 1 in 4 chance, or a 25% probability, that their child will inherit the blue eye genotype (bb) and therefore have blue eyes.
The Punnett square for crossing two heterozygous dogs (Bb x Bb) would result in a 25% chance of offspring with homozygous dominant black fur (BB), a 50% chance of offspring with heterozygous black fur (Bb), and a 25% chance of offspring with homozygous recessive brown fur (bb).
Assuming that you mean heterozygous for blue/brown eyes, 50%.
Both parents were heterozygous (Bb). The offspring would statistically be: BB, Bb, Bb, and bb. All but the bb offspring would be black and the bb would be brown.
are likely heterozygous for eye color. This means you have two different alleles for eye color - one for brown eyes and one for blue eyes. The dominant allele for brown eyes may result in you having brown eyes, but you still carry the blue eye allele.
a brown horse i just did this in school a few weeks ago
i think you are asking for the outcome of the offspring, yes? The meathod that i know is to use a punnent square. A punnet square uses the probability to test the genotype (genetic makeup) and phenotype (physical characteristics. You can Google "punnet square" if you wish, to get a full description and how to make one. Here are my results*: there is a... 100% chance of a baby black rabbit (assuming that the black hair is domonant) 75% chance the baby will be homozygous (domonant,pure) 25% chance the baby will be heterozygous (domonant, hybrid) *these results are very general and i am assuming that there is no blending of the traits. (like a gray bunny!) Hope this helped!
75%
The probability that he or she will have brown eyes and blond hair is 21/50.