I would call it something like 2-bromo propanoic acid
The compound Br-CH2-CH=CH2 is 3-bromo propene.
Because this compund known as ( Ethyl Bromide)
The IUPAC name is 1,3-dibromobutane
It is 2-bromo pentane
This compound is bromobutane.
CH3-CH2-CH2-Br + KOH(alcoholic) = CH3-CH=CH2 + KCl + H2O CH3-CH=CH2 + HBr = CH3-CH(Br)-CH3 Markonikov's rule
Br Br | |H - C - C - H| |H H
onvert the ethyl bromide into Grignard's reagent, ethyl magnesium bromide then allow to react with dry ice (Solid carbon dioxide) then acidic hydrolysis produces the propionic acid. CH3-Br + Mg --- anhydrous ether---> CH3-CH2-Mg-Br CH3-CH2-Mg-Br + CO2 ----H+/H2O---> CH3-CH2-COOH
CH2=CH2-CH-CH2-Br 1-butene, 3- OH, 4-Br | OH Not sure but would be my best bet
The molecule CH3-HC=CH-Br can exist either in the cis or trans configuration.
Ethylbromide is the name of the compound CH3-CH2-Br.
1 - bromopropane is the IUPAC name for CH3-CH2-CH2-CH2-Br.
The compound Cl-CH2-CH2-CH2-CH=CH-CH2-Br is 1-bromo-6-chloro-2-hexene.
CH3-CH2-CH2-Br + KOH(alcoholic) = CH3-CH=CH2 + KCl + H2O CH3-CH=CH2 + HBr = CH3-CH(Br)-CH3 Markonikov's rule
CH3-CH=CH-CH2-CH3 + Br2 = CH3-CH(Br)-CH(Br)-CH2-CH3
Br Br | |H - C - C - H| |H H
Convert the ethyl bromide into Grignard's reagent, ethyl magnesium bromide then allow to react with dry ice (Solid carbon dioxide) then acidic hydrolysis produces the propionic acid. CH3-Br + Mg --- anhydrous ether---> CH3-CH2-Mg-Br CH3-CH2-Mg-Br + CO2 ----H+/H2O---> CH3-CH2-COOH
1-dehydrohalogenation of n-propylbromide which gives the propene. CH3-CH2-CH2-Br + KOH(Alcoholic) -----> CH3-CH=CH2 2-again hydrohalogenation with HBr gives mostly iso-propylbromide,(Markonikov's rule). CH3-CH=CH2 + HBr ------> CH3-CHBr-CH3 3-The reaction of iso-propylbromide with Sodium metal in presence of anhydrous ether (Wurtz reaction) gives the 2,3-dimethylbutane. 2(CH3-CHBr-CH3) + 2Na ---anhydrous ether--->CH3-CHCH3-CHCH3-CH3
Br-CH2-CH2-C=-C-CH2-CH3
Ch3ch2ch2ch2br + NaOH -> ch3ch2ch2ch2oh + NaBr
onvert the ethyl bromide into Grignard's reagent, ethyl magnesium bromide then allow to react with dry ice (Solid carbon dioxide) then acidic hydrolysis produces the propionic acid. CH3-Br + Mg --- anhydrous ether---> CH3-CH2-Mg-Br CH3-CH2-Mg-Br + CO2 ----H+/H2O---> CH3-CH2-COOH
The redish brown bromine color disappears by the addition of bromine to double bond.Br2 + H2C==CH-(CH2)n-CH3 ----> H2C(Br)--CH(Br)-(CH2)n-CH31-alkene ----> 1,2-dibroom-alkane