The chemical equation for the reaction between barium and selenium is: Ba + Se → BaSe. This reaction forms barium selenide.
The compound AI2S3 is called aluminum sulfide. It is an inorganic compound composed of two aluminum atoms bonded to three sulfur atoms.
AI2S3 is the chemical formula for aluminum sulfide, a compound composed of aluminum and sulfur atoms. It is a gray or white solid that is insoluble in water and can be used in various industrial applications, such as in the production of aluminum metal.
To balance the reaction between sodium phosphate (Na₃PO₄) and barium nitrate (Ba(NO₃)₂), the coefficients are 2 for Na₃PO₄ and 3 for Ba(NO₃)₂. The balanced equation is: 2 Na₃PO₄ + 3 Ba(NO₃)₂ → 6 NaNO₃ + Ba₃(PO₄)₂. This ensures that the number of each type of atom is equal on both sides of the equation.
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
Probably as a Displacement reaction
The reaction between barium (Ba) and phosphorus (P) would form barium phosphide (Ba3P2) as the product.
Aluminum Sulfide
The chemical equation for the reaction between barium and selenium is: Ba + Se → BaSe. This reaction forms barium selenide.
The compound AI2S3 is called aluminum sulfide. It is an inorganic compound composed of two aluminum atoms bonded to three sulfur atoms.
Assuming you have given a complete equation, no. It requires oxygen as a reactant and will always have CO2 and H2O as products. Plus, combustion reactions typically involve carbon based elements as reactants.
Ba(OH)2 + H2SO4 react to form BaSO4 + 2H2O
Ba + 2H2O → Ba(OH)2 + H2.
AI2S3 is the chemical formula for aluminum sulfide, a compound composed of aluminum and sulfur atoms. It is a gray or white solid that is insoluble in water and can be used in various industrial applications, such as in the production of aluminum metal.
It is an Ionic compound.
If ba = 2a + b , then find 23 + 32 +1
To balance the reaction between sodium phosphate (Na₃PO₄) and barium nitrate (Ba(NO₃)₂), the coefficients are 2 for Na₃PO₄ and 3 for Ba(NO₃)₂. The balanced equation is: 2 Na₃PO₄ + 3 Ba(NO₃)₂ → 6 NaNO₃ + Ba₃(PO₄)₂. This ensures that the number of each type of atom is equal on both sides of the equation.