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A 3.0 lamp and a 6.0 lamp are connected in serieswhat is the total resistance of the combination?
In a series circuit, the total resistance is the sum of the individual resistances. So, the total resistance of the 3.0 lamp and 6.0 lamp connected in series would be 3.0 + 6.0 = 9.0 ohms.
Can you connect a 20 watt lamp directly to a 12 volt dry cell?
If it's a 12V lamp - sure. But, depending on the battery and the complexity of the installation it might be wise to put a fuse in the circuit too, right up by the battery.
When you turn on a lamp are you opening or closing a circuit?
When you turn on a lamp, you are closing the circuit. This allows electricity to flow from the power source, through the lamp, and back to the power source, enabling the lamp to light up.
What is the resistance value for LED bulb in 12v DC circut?
The resistance value for an LED bulb in a 12V DC circuit can vary depending on the specific LED bulb used. Generally, LEDs have very low resistance values due to their semiconductor nature. It is more common to use a current-limiting resistor in series with the LED to control the current and prevent damage to the LED.
What is lamp circuit?
A lamp circuit is an electrical circuit designed to power a lamp, allowing it to produce light. It typically consists of a power source, such as a battery or mains electricity, connected to a light bulb through a switch and wiring. The circuit can be simple, with just a switch and a bulb, or more complex, incorporating dimmers or smart controls. When the circuit is closed by the switch, electricity flows to the lamp, illuminating it.
If a 12 volt parallel circuit has 4 lamps and each lamp consumes 1 amp what is the resistance of each lamp?
Assuming you mean the 4 lamps are in parallel with each other: the total voltage drop across each lamp is still 12V. As we know that V= IR (Voltage = I Current times Resistance) 12 = 1 x R so Resistance = 12 Ohms for each lamp.
If each lamp is rated 12v 24w what is the current consumed by each lamp?
2 amperes in a parallel circuit. I = W/V. It is true provided that 12v are delivered to the lamps in parallel circuit. In a series circuit, the voltage is divided among the lamps so that the total current is probably 2 amperes for all lamps.
A 3.0 lamp and a 6.0 lamp are connected in serieswhat is the total resistance of the combination?
In a series circuit, the total resistance is the sum of the individual resistances. So, the total resistance of the 3.0 lamp and 6.0 lamp connected in series would be 3.0 + 6.0 = 9.0 ohms.
I need to draw a circuit diagram to show this but I have no idea how do you find the resistance of a lamp in a circuit?
If you have a lamp, you can assume that the resistance of the lamp when it is under power will follow the ohms law. BUT, one thing you must remember is, when a lamp is under load, it is glowing HOT. When metal is HOT, the molculoes of the meals are in much more active state. When this happens, the resistance will increase. Conversely, when the lamp is NOT on ON state, the filaments are cold. Moleculoes in the filaments are not as active. Thus, the resistance is lower. There is almost 10 to 1 difference in resistance from hot to cold. Taking out a multimeter and measuring the resistance of the lamp will not help you determine the resistance of the lamp when it is actually under load (with voltage applied) Really, the only thing you can do is to measure the voltage, measure the current, then arrive at the resistance mathmatically.
When the thermistor in the circuit is heated the lamp becomes brighter why does this happen?
When the thermistor in the circuit is heated, its resistance decreases due to the negative temperature coefficient of thermistors. This reduction in resistance allows more current to flow through the circuit. As a result, the increased current causes the lamp to receive more power, leading to a brighter illumination.
What happens to the ammeter reading when a lamp is added to a circuit which contains two cells and a lamp in series?
Assuming the new lamp is in series, the ammeter reading falls because the total resistance has increased. By how much depends on how the lamp resistance depends on voltage. If the lamp is added in parallel to the first, then the ammeter reading doubles.
When a 12 V battery is connected across an unknown resister there is a current of 2.5 mA in the circuit find the value of the resistance of the resistor?
Resistance = voltage / current = 12V / 2.5mA = 12V / (2.5 x 10-3 A) = 4.8 x 103 ohm
What will be the amps of a 12v 2amp circuit if there is a 12ohm resistor on it?
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
How do you control the brightness of a lamp in a circuit?
You can control the brightness of a lamp in a circuit by adjusting the amount of current flowing through it. This can be done using a variable resistor such as a potentiometer or a dimmer switch. By changing the resistance in the circuit, you can regulate the current and therefore the brightness of the lamp.
Can you connect a 20 watt lamp directly to a 12 volt dry cell?
If it's a 12V lamp - sure. But, depending on the battery and the complexity of the installation it might be wise to put a fuse in the circuit too, right up by the battery.
How does a 6volt relay circuit works?
The same as a 12V relay circuit, except it only needs 6V instead of 12V.
To run 12v dc things in a car the battery outputs 12v regularly but it can go as high as 14.4 when the engine is running I need a circuit to regulate this at say 12v 10 amps to prevent over voltage?
the alternator is what puts out the 14.4 volts. if you wish to figure out the circuit use the formula A*R=V so you take the voltage 12 divide by the amp 12 and you get 1.2 as the resistance. so in your circuit, the max allowable load is 1.2 ohms.
